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Reptile [31]
3 years ago
8

Jamie can read at a speed of 65 pages per hour. If she reads a novel that has 400 pages, how long will it

Mathematics
1 answer:
horsena [70]3 years ago
8 0
To find the answer set up an equation:
400 \: pages \times  \frac{1 \: hour}{65 \: pages}  =
Using this set up we can cross our units of pages since they are on opposite side of the proportion, leaving us with the desired units of hours.

Then divide 400 by 65 which will give us our answer: 6.15 or about 6 hours for Jamie to finish her reading.
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Umm was there supposed to be another picture
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3 years ago
Solve this equation for x. Round your answer to<br>the nearest hundredth.<br>7 = In(x + 5)<br>​
oksian1 [2.3K]

Answer:

x ≈ 1091.63

Step-by-step explanation:

Using the rule of logarithms

log_{b} x = n ⇔ x = b^{n}

note that ln x is to the base e

Given

ln(x + 5) = 7, then

x + 5 = e^{7} ( subtract 5 from both sides )

x = e^{7} - 5 ≈ 1091.63 ( nearest hundredth )

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3 years ago
Which of the following graphs is the inverse of f(x) = x2 + 4?
Eddi Din [679]

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Step-by-step explanation:

5 0
3 years ago
At Burnt Mesa Pueblo, archaeological studies have used the method of tree-ring dating in an effort to determine when prehistoric
Zanzabum

Answer:

a) (1215, 1297)

b) (1174,  1338)

c) (1133, 1379)      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1256

Standard Deviation, σ = 41

Empirical Rule:

  • Also known as 68-95-99.7 rule.
  • It states that almost all the data lies within three standard deviation for a normal data.
  • About 68% of data lies within 1 standard deviation of mean.
  • About 95% of data lies within two standard deviation of mean.
  • About 99.7% of data lies within 3 standard deviation of mean.

a) range of years centered about the mean in which about 68% of the data lies

\mu \pm 1(\sigma)\\=1256 \pm 41\\=(1215, 1297)

68% of data will be found between 1215 years and 1297 years.

b) range of years centered about the mean in which about 95% of the data lies

\mu \pm 2(\sigma)\\=1256 \pm 2(41)\\=1256 \pm 82\\=(1174, 1338)

95% of data will be found between 1174 years and 1338 years.

c) range of years centered about the mean in which about all of the data lies

\mu \pm 3(\sigma)\\=1256 \pm 3(41)\\=1256 \pm 123\\=(1133, 1379)

All of data will be found between 1133 years and 1379 years.

3 0
3 years ago
The GCF of 24 and 32 is
Oksana_A [137]

Start by setting up a factor tree for each number.

Factor in anyway that you'd like.

At the end, circle all prime numbers.

Remember, prime numbers are numbers

with only 2 factors, 1 and the number itself.

Now write these factors in least to greatest

multiplying them separate rows.

Circle factors they have in common.

Since 3 pairs of two's match up, multiply by 2 three times to get 8.

So the GCF is 8.

4 0
3 years ago
Read 2 more answers
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