5s subshell represent that n is equal to 5 and l is equal to 0.
2p subshell represent that n is equal to 2 and l is equal to 1.
3d subshell represent that n is equal to 3 and l is equal to 2.
The numbers gives us the value of n and the letter gives us the value of l.
s means l = 0
p means l = 1
d means l = 2
f means l = 3
Answer:85.5
Step-by-step explanation:
Use calculator
Answer:
(a) There are outliers
(b)
and ![x >62](https://tex.z-dn.net/?f=x%20%3E62)
Step-by-step explanation:
Given
![\sigma = 14.92](https://tex.z-dn.net/?f=%5Csigma%20%3D%2014.92)
![\bar x = 22.0](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%2022.0)
![q_0 = -24](https://tex.z-dn.net/?f=q_0%20%3D%20-24)
![q_1 = 14.5](https://tex.z-dn.net/?f=q_1%20%3D%2014.5)
![q_2 = 24.5](https://tex.z-dn.net/?f=q_2%20%3D%2024.5)
![q_3 = 33.5](https://tex.z-dn.net/?f=q_3%20%3D%2033.5)
![q_4 = 64](https://tex.z-dn.net/?f=q_4%20%3D%2064)
Solving (a): Check for outliers
This is calculated using:
--- lower bound of outlier
--- upper bound of outlier
Where
![IQR = Q_3 - Q_1](https://tex.z-dn.net/?f=IQR%20%3D%20Q_3%20-%20Q_1)
So, we have:
![IQR = 33.5 - 14.5](https://tex.z-dn.net/?f=IQR%20%3D%2033.5%20-%2014.5)
![IQR = 19](https://tex.z-dn.net/?f=IQR%20%3D%2019)
The lower bound of outlier becomes
![Lower = Q_1 - (1.5 * IQR)](https://tex.z-dn.net/?f=Lower%20%3D%20Q_1%20-%20%281.5%20%2A%20IQR%29)
![Lower = 14.5 - (1.5 * 19)](https://tex.z-dn.net/?f=Lower%20%3D%2014.5%20-%20%281.5%20%2A%2019%29)
![Lower = 14.5 - 28.5](https://tex.z-dn.net/?f=Lower%20%3D%2014.5%20-%2028.5)
![Lower = -14](https://tex.z-dn.net/?f=Lower%20%3D%20-14)
The upper bound of outlier becomes
![Upper = Q_3 +(1.5 * IQR)](https://tex.z-dn.net/?f=Upper%20%3D%20Q_3%20%2B%281.5%20%2A%20IQR%29)
![Upper = 33.5 + 1.5 * 19](https://tex.z-dn.net/?f=Upper%20%3D%2033.5%20%2B%201.5%20%2A%2019)
![Upper = 33.5 + 28.5](https://tex.z-dn.net/?f=Upper%20%3D%2033.5%20%2B%2028.5)
![Upper = 62](https://tex.z-dn.net/?f=Upper%20%3D%2062)
So, we have:
--- the range without outlier
Given that:
--- This represents the lowest data
--- This represents the highest data
-24 and 64 are out of range of
.
Hence, there are outliers
Solving (b): The outliers
The outliers are data less than the lower bound (i.e. less than -14) or greater than the upper bound (i.e. 62)
So, the outliers are:
and ![x >62](https://tex.z-dn.net/?f=x%20%3E62)
Answer:
A radius of a circle or sphere is any of the line segments from its center to its perimeter, and in more modern usage, it is also their length
Step-by-step explanation:
7. 324m squared
8. 166mm squared
9. 49.2yd squared
sorry I'm too lazy to do the rest