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2 years ago

What is 300/250 simplest form?

Mathematics

1 answer:

EleoNora [17]2 years ago

7 0

300\250

1.2

or

6\5

I hope this help

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For f(x)= x +2 and g(x)= 1/x find (g o f)

lukranit [14]

Hello :
<span>f(x)= x +2 and g(x)= 1/x
</span><span>(g o f)(x) = g(f(x))=g(x+2) = 1/(x+2)</span>

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3 years ago

If a point B(2,5) lies on a circle with center at origin,then what will be the length of the

lianna [129]

Answer:

r = $\sqrt{29}$

Step-by-step explanation:

The distance from the centre to a point on the circle is the radius r

Calculate r using the distance formula

r = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = (0, 0 ) and (x₂, y₂ ) = (2, 5 )

r = $\sqrt{(2-0)^2+(5-0)^2}$

= $\sqrt{2^2+5^2}$

= $\sqrt{4+25}$

= $\sqrt{29}$

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2 years ago

Monica took a survey of her classmates' hair and eye color. The results are in the table below.

katrin2010 [14]

Answer: 0.5

Step-by-step explanation: it should be but wait for other answers

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2 years ago

Amy's grandmother gave her 3 identical chocolate chip cookies and 4 identical sugar cookies. In how many different orders can Am

Dmitrij [34]

Answer:

chocolate chip cookie first: 15 ways

chocolate chip cookie last: 15 ways

chocolate chip cookie first and last: 5 ways

Step-by-step explanation:

There is a total of 7 cookies.

Is she eats a chocolate cookie first, she will have 2 chocolate cookies and 4 sugar cookies (6 in total).

So, to find the number of different orders that Amy can eat the remaining cookies, we just need to calculate a combination of 6 choose 2 (that is, the number of ways we can put the 2 chocolate cookies among the 6 cookies) or a combination of 6 choose 4 (same thing, but for the sugar cookies):

C(6,2) = 6! / (2! * 4!) = 6 * 5 / 2 = 15 ways

Is she eats a chocolate cookie last, she will have 2 chocolate cookies and 4 sugar cookies (6 in total), so the problem is solved again with a combination of 6 choose 2:

C(6,2) = 15 ways

Is she eats a chocolate cookie first and last, she will have just 1 chocolate cookie left and 4 sugar cookies (5 in total), so the problem is solved with a combination of 5 choose 1 or a combination of 5 choose 4:

C(5,1) = 5! / (1! * 4!) = 5 ways

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2 years ago

Kinda putting this out here to everyone so you can learn. Don't just click on a person needing help then guess or just put gibbe

ElenaW [278]

Really true. just wanting points is not a reason to mess with someone else.

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3 years ago