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oksian1 [2.3K]
3 years ago
14

Compare the linear functions expressed below by data in a table and by an equation.

Mathematics
1 answer:
kondor19780726 [428]3 years ago
7 0

Answer:

b,c,e

Step-by-step explanation:

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Which would be used to solve this equation? Check all that apply.
puteri [66]

Answer:

multiplying both-side of the equation by 3

substituting 36 for p to check the solution

Step-by-step explanation:

To solve the equation p/3 = 12, we will follow the steps below;

first multiply 3 to both-side of the equation, that is:

p/3 × 3 = 12 × 3

On the left-hand side of the equation, 3 at the numerator will cancel-out 3 at the denominator, leaving us with just p while on the right-hand side of the equation 12 will be multiplied by 3

p= 36

To check the correctness of the equation, we can substitute p = 36 back into the equation and then check, that is;

p/3 = 12

36/3 = 12

This implies p = 36 is correct

3 0
3 years ago
Q1. In a fruit cocktail, for every 30 ml
lora16 [44]

Answer:

3/10

Step-by-step explanation:

\frac{30}{30 + 20 + 50}   =  \frac{3}{10}

5 0
3 years ago
Question 7
Sedbober [7]

Answer:

1.27

Step-by-step explanation:

In Centimeter It's 127 Just Put A Decimal! :)

5 0
3 years ago
Fill in the missing reason for the last step.
jek_recluse [69]

Answer:

Division

Step-by-step explanation:

You divided both sides of the inequality by -3. Multiplying/dividing by negative numbers change the sign of the inequality, so you have ">" turned into "<".

6 0
4 years ago
Find the area of the shaded region
Alex777 [14]

∆BOC is equilateral, since both OC and OB are radii of the circle with length 4 cm. Then the angle subtended by the minor arc BC has measure 60°. (Note that OA is also a radius.) AB is a diameter of the circle, so the arc AB subtends an angle measuring 180°. This means the minor arc AC measures 120°.

Since ∆BOC is equilateral, its area is √3/4 (4 cm)² = 4√3 cm². The area of the sector containing ∆BOC is 60/360 = 1/6 the total area of the circle, or π/6 (4 cm)² = 8π/3 cm². Then the area of the shaded segment adjacent to ∆BOC is (8π/3 - 4√3) cm².

∆AOC is isosceles, with vertex angle measuring 120°, so the other two angles measure (180° - 120°)/2 = 30°. Using trigonometry, we find

\sin(30^\circ) = \dfrac{h}{4\,\rm cm} \implies h= 2\,\rm cm

where h is the length of the altitude originating from vertex O, and so

\left(\dfrac b2\right)^2 + h^2 = (4\,\mathrm{cm})^2 \implies b = 4\sqrt3 \,\rm cm

where b is the length of the base AC. Hence the area of ∆AOC is 1/2 (2 cm) (4√3 cm) = 4√3 cm². The area of the sector containing ∆AOC is 120/360 = 1/3 of the total area of the circle, or π/3 (4 cm)² = 16π/3 cm². Then the area of the other shaded segment is (16π/3 - 4√3) cm².

So, the total area of the shaded region is

(8π/3 - 4√3) + (16π/3 - 4√3) = (8π - 8√3) cm²

7 0
2 years ago
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