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Romashka [77]
4 years ago
5

angle EFG and angle GFH are a linear pair, m angle GFH= 2n+38 and m angle GFH=2n+38. what are m angle EFG and m angle GFH

Mathematics
2 answers:
givi [52]3 years ago
7 0

Answer:

m

m

Step-by-step explanation:

angle EFG and angle GFH are a linear pair

m<EFG +m<GFH = 180 degree because it is linear pair

m<EFG= 3n+22 and m<GFH=2n+38

m<EFG +m<GFH = 180

3n+22+2n+38=180

Combine like terms

5n+60=180

Subtract 60 from both sides

5n=120

Divide both sides by 5

n=24

m

m

motikmotik4 years ago
5 0

Answer:

Part 1) m∠EFG=94°

Part 2) m∠GFH=86°

Step-by-step explanation:

we know that

m∠EFG+m∠GFH=180° -----> by linear pair (given problem)

we have

m∠EFG=3n+22

m∠GFH=2n+38

substitute the values

(3n+22)°+(2n+38)°=180°

Solve for n

(5n+60)=180

5n=180-60

5n=120

n=24

<em>Find the measure of angle EFG</em>

m∠EFG=3n+22

substitute the value of n

m∠EFG=3(24)+22=94°

<em>Find the measure of angle GFH</em>

m∠GFH=2n+38

substitute the value of n

m∠GFH=2(24)+38=86°

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Step-by-step explanation:

For every increase of 1 in the X value of the graph, the Y value increases by 4, so the slope would be \frac{4}{1} or 4.

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3 years ago
How many 9 digit palindromes are there with all the digits being even and each digit appearing no more than once
likoan [24]

Answer:

96

Step-by-step explanation:

We have to find number of 9 digit palindromes  when all digits are even and each digit appearing not more than twice.

Digits used here

0,1,2,3,4,5,6,7,8,9

Total number of even digits=0,2,4,6,8=5

Now,

0 cannot be used for first place if number is 9-digit number.

Firs place can be filled by number of ways=4

Second place can be filled by number of ways=4

Third place can be filled by number of ways=3

Fourth place can be filled by number of ways=2

Fifth place can be filled by number of ways=1

Total number of ways=4\times 4\times 3\times 2\times 1

Total number of ways=96

Hence, total number of 9-digits palindromes  when all digits are even and appearing not more than twice=96

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3 years ago
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sergij07 [2.7K]
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kotykmax [81]
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Answer:

\dfrac{2}{5}m-\dfrac{1}{5}

Step-by-step explanation:

First, use the distributive property a\cdot (b-c)=a\cdot b-a\cdot c. Thus,

2\cdot \left(\dfrac{1}{5}m-\dfrac{2}{5}\right)=2\cdot \dfrac{1}{5}m-2\cdot \dfrac{2}{5}=\dfrac{2}{5}m-\dfrac{4}{5}.

Then given expression will take look

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This expression consists of three terms, one term with m and two terms without m. Combine terms without m:

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Therefore, an equivalent expression is

\dfrac{2}{5}m-\dfrac{1}{5}.

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