Question

It took 16 seconds for a mercury thermometer to rise from negative degrees to 100 degrees when it was taken from a freezer and placed in boiling water. Show that somewhere along the way the mercury was rising at the rate of 6.5degrees​C/second.

Answer 1

Answer:

$m = \frac{100 -(-4)}{16-0 s}= \frac{104 C}{16s}= 6.5 \frac{C}{s}$

Step-by-step explanation:

Assuming the complete question :"It took 16 seconds for a mercury thermometer to rise from -4C degrees to 100C degrees when it was taken from a freezer and placed in boiling water. Show that somewhere along the way the mercury was rising at the rate of 6.5degrees​C/second. "

For this case we can find the rate of change like this:

$m = \frac{T_f -T_i}{t_f -t_i}$

For this cas we have the following data:

$T_i = -4 C$ represent the initial temperature

$T_f = 100 C$ represent the final temperature

$t_i =0 s$ we assume that we star at 0 seconds

$t_f = 16 s$ represent the final time

So we can replace the info and we got:

$m = \frac{100 -(-4)}{16-0 s}= \frac{104 C}{16s}= 6.5 \frac{C}{s}$

And that satisfy the proof.