Answer:
The mean of A and C is equal to 10.
Step-by-step explanation:
We know that,
![\text{Mean}=\dfrac{\text{Sum of observations}}{\text{Total no of obervations}}](https://tex.z-dn.net/?f=%5Ctext%7BMean%7D%3D%5Cdfrac%7B%5Ctext%7BSum%20of%20observations%7D%7D%7B%5Ctext%7BTotal%20no%20of%20obervations%7D%7D)
The mean of A and B is 20,
![A+B=20\\\\A+B=40\ \ .........(1)](https://tex.z-dn.net/?f=A%2BB%3D20%5C%5C%5C%5CA%2BB%3D40%5C%20%5C%20.........%281%29)
The mean of B and C is 24,
![B+C=24\times 2\\\\B+C=48\ \ .........(2)](https://tex.z-dn.net/?f=B%2BC%3D24%5Ctimes%202%5C%5C%5C%5CB%2BC%3D48%5C%20%5C%20.........%282%29)
The mean of A,B and C is 18,
![A+B+C=18\times 3\\\\A+B+C=54\ .....(3)](https://tex.z-dn.net/?f=A%2BB%2BC%3D18%5Ctimes%203%5C%5C%5C%5CA%2BB%2BC%3D54%5C%20.....%283%29)
Put the value of A+B from (1) in (3),
C = 14
Put the value of B+C from (2) in (3)
A = 6
Mean of A and C is :
![M=\dfrac{A+C}{2}\\\\M=\dfrac{14+6}{2}\\\\M=10](https://tex.z-dn.net/?f=M%3D%5Cdfrac%7BA%2BC%7D%7B2%7D%5C%5C%5C%5CM%3D%5Cdfrac%7B14%2B6%7D%7B2%7D%5C%5C%5C%5CM%3D10)
So, the mean of A and C is equal to 10.
17.25
...............................
Ok sooo. I think the answer is A.
A.) 180 degrees
The histogram that represents the data with the largest spread is Data Set B