To find the midpoint, add both x values together and divide by two and then add both y values together and divide by two.
Midpoint X = (-3 +4)/2 = 1/2
Midpoint y = (-4 + -1)/2 = -5/2
Midpoint = (1/2, -5/2)
Area of a rectangle of length L and width W is A = LW.
Here, A = 60 ft^2 = (12 ft)(2x-3 ft). Let's find the values of x for which the area =60 ft^2, and then the values of x for which the area is greater than 60 ft^2.
60 = 12(2x-3) becomes 5 = 2x - 3 after dividing both sides by 12.
Adding 3 to both sides of this last equation results in 8 = 2x, so x = 4.
Does (12 ft)(2[4 ft] - 3) = 60? Does (12 ft)(5 ft) = 60 sq ft? YES.
The area of this rectangle will be greater than 60 sq ft if x>4 ft. (answer)
I know that b and d are correct because c is just silly and a is just incorrect :)
they are the same lines
x and y are the same
Step-by-step explanation:
i dont know for sure so bye god bless
