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Marat540 [252]
3 years ago
7

Calculate the height of an equilateral triangle with side is 8 cm long​

Mathematics
1 answer:
Greeley [361]3 years ago
8 0

Step-by-step explanation:

use pythagoras theorem for finding the height

hypotenuse is 8cm

base is 4 cm

height?

a^2+b^2=c^2

64-16=a^2

a=7.07cm

Height of equilateral triangle is 7.07cm

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Shalnov [3]

Answer:

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Step-by-step explanation:

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2 years ago
PLEASE HELP ASAPPP<br> which systems of equations represents the matrix shown below??
natka813 [3]

Answer:

The answer to your question is the last choice.

Step-by-step explanation:

The first column represents the x

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The third column represents the z

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The second line represents the second equation

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5 0
3 years ago
Read 2 more answers
The car is moving with a speed v0 = 48 mi/hr up the 4-percent grade, and the driver applies the brakes at point A, causing all w
lutik1710 [3]

Answer:

s = 0.2203 miles

Step-by-step explanation:

Given:

- The initial speed vo = 48 mi/hr

- The mass of the car m

- The coefficient of kinetic friction uk = 0.61

- The slope of the road 4-percent grade

Find:

Determine the stopping distance sAB. Repeat your calculations for the case when the car is moving downhill from B to A.

Solution:

- Apply the energy principle with work done against friction:

                             K.E_1 + P.E_1 = Wf + P_E_2 + K.E_2

- The final velocity of car is zero, K.E_2 = 0

  The initial potential energy is set as zero, P.E_1 = 0

                             K.E_1 = Wf + P_E_2

                             0.5*m*vo^2 = Ff*s + m*g*h

Where, Ff is the frictional force:

                             Ff = uk*N

Where, N is the normal contact force between car and road. By equilibrium equation we have:

                             m*g*cos(θ) - N = 0

                             N = m*g*cos(θ)

Hence,

                             Ff = uk*m*g*cos(θ)

- The vertical distance travelled h is:

                             h = s*sin(θ)

- The energy equation is:

                             0.5*m*vo^2 = uk*m*g*cos(θ)*s + m*g*s*sin(θ)

                             0.5*vo^2 = uk*g*cos(θ)*s + g*s*sin(θ)

                             s*(uk*g*cos(θ) + g*sin(θ) ) = 0.5*vo^2

                             s = [0.5*vo^2 / (uk*g*cos(θ) + g*sin(θ) ) ]

- The slope = 4 / 100,

                      s = [0.5*48^2 / (0.61*8052.97*cos(2.29) + 8052.97*sin(2.29) ) ]

                      s = 0.2203 miles

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3 years ago
Find the slope of the line through the points (12, -9) &amp; (-11, -9)
marin [14]

Answer:

0

Step-by-step explanation:

7 0
2 years ago
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