Question

A triangle has a base of 3⅖ inches and an area of 5⅒ square inches. Find the height of the triangle. Show your reasoning

Answer 1

Answer: 3 in.

Step-by-step explanation:

Given

The base of the triangle is $3\frac{2}{5}\ inches$

The area of the triangle is $5\frac{1}{10}\ inches^2$

Solve mixed fraction

Base is

$=3\dfrac{2}{5}\\\\=\dfrac{17}{5}\ in.$

Area is

$=5\dfrac{1}{10}\\\\=\dfrac{51}{10}\ in.^2$

The area of the triangle is given by

$\Rightarrow \text{Area A=}\dfrac{1}{2}\times \text{base}\times \text{height}$

Insert the values to get the height

$\Rightarrow \dfrac{51}{10}=\dfrac{1}{2}\times \dfrac{17}{5}\times \text{height}\\\\\Rightarrow \text{height}=3\ in.$