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nikdorinn [45]
1 year ago
13

Find the area of Bedroom #3 and the cost of hardwood floors in Bedroom #3 at $7.24 per sq ft. (round toSECOND FLOOR10.5 ftEHIF14

ftBEDROOMWOPEN TOLONOFFICEwwww11.5 ft13 ftArea of Bedroom #3 =Cost of floors in Bedroom #3 = $17 ftBEDROOMwww10.5 ftft²BEDROOM #WOW13 ft

Mathematics
1 answer:
dangina [55]1 year ago
7 0

Solution:

The dimensions of the bedroom #3 are given below as

\begin{gathered} l=13ft \\ w=10.5ft \end{gathered}

To calculate the area of the bedroom, we will us eth formula below

\begin{gathered} A=l\times w \\ A=13ft\times10.5ft \\ A=136.5ft^2 \end{gathered}

Hence,

The area of BEDROOM #3 is

\Rightarrow136.5ft^2

Part B:

Given that the cost of the floor is

\begin{gathered} \text{ \$}7.24=1ft^2 \\ x=136.5ft^2 \\ cross\text{ multiply, we will have} \\ x=136.5\times\text{ \$}7.24 \\ x=\text{ \$}988.26 \end{gathered}

Hence,

The cost of floors of bedroom #3 is

\Rightarrow\text{ \$}988.26

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svetlana [45]

Answer:  The required solution is

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Step-by-step explanation:   We are given to solve the following differential equation :

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Let us consider that

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Substituting these values in equation (i), we get

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So, the general solution of the given equation is

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Differentiating with respect to t, we get

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According to the given conditions, we have

y(0)=-2\\\\\Rightarrow A=-2

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Thus, the required solution is

y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.

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