In order to find height from where ball is dropped, you have to find height or h(t) when time or t is zero.So plug in t=0 into your quadratic equation:h(0) = -16.1(0^2) + 150h(0) = 0 +150h(0) = 150 ft is the height from where ball is dropped. When ball hits the ground, the height is zero. So plug in h(t) = 0 and solve for t.0 = -16.1t^2 + 15016.1 t^2 = 150t^2 = 150/16.1t = sqrt(150/16.1)t = ± 3.05Since time cannot be negative, your answer is positive solution i.e. t = 3.05
Answer:
3(x+1)-4x=3(2x+1)-7x = True
Step-by-step explanation:
Answer:
Option A
Step-by-step explanation:
A = 3 +3 +3+3 = 12
B = 3⁴ = 81
C = 3² × 3² = 9 × 9 = 81
D = 3× 3 × 3 × 3 = 81
Answer:
556.2% change
Step-by-step explanation:
Percentage change = (p2-p1)/p1 * 100%
= (58.99 - 8.99) / 8.99 * 100%
= 556.2% change
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Answer:
h = 7.1 cm
Step-by-step explanation:
To find the height of the triangle, we can first find the area of the triangle using the Heron's formula:
Where a, b and c are the sides of the triangle and p is the semi perimeter of the triangle:
So the area of the triangle is:
Now, to find the height, we can use the following equation for the area of the triangle:
The height draw in the figure is relative to the side of 17 cm, so this side is the value of base used in the formula. So we have that:
Rounding to the nearest tenth, we have h = 7.1 cm
