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ss7ja [257]
3 years ago
13

Simplify the product using the distributive property. (4h+6)(4h-7)

Mathematics
2 answers:
Inessa05 [86]3 years ago
6 0
<span>(4h+6)(4h-7)
= 16h^2 + 24h - 28h - 42
= 16h^2 - 4h - 42

hope it helps</span>
GalinKa [24]3 years ago
4 0

Answer:

the product using the distributive property. (4h+6)(4h-7) is, 16h^2-4h-42

Step-by-step explanation:

The distributive property says that:

a \cdot (b+c) =a\cdot b+ a\cdot c

To find the product:

(4h+6)(4h-7)

then;

4h(4h-7)+6(4h-7)

Apply the distributive property we have;

16h^2-28h+24h-42

Combine like terms we have;

16h^2-4h-42

therefore, the product using the distributive property. (4h+6)(4h-7) is, 16h^2-4h-42

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What is the area of angle GHI
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6.4

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We have seen that isosceles triangles have two sides of equal length. The angles opposite these sides have the same measure. Use
Naddik [55]

Question has missing figure, the figure is in the attachment.

Answer:

The measure of ∠1 is 65°.

The measure of ∠2 is 65°.

The measure of ∠3 is 50°.

The measure of ∠4 is 115°.

The measure of ∠5 is 65°.

Step-by-step explanation:

Given,

We have an isosceles triangle which we can named it as ΔABC.

In which Length of AB is equal to length of BC.

And also m∠B is equal to m∠C.

ext.m∠C= 115°(Here ext. stands for exterior)

We have to find the measure of angles angles 1 through 5.

Solution,

For ∠1.

∠1 and ext.∠C makes straight angle, and we know that the measure of straight angle is 180°.

So, we can frame this in equation form as;

\angle1+ext.\angle C=180\°

On putting the values, we get;

\angle 1+115\°=180\°\\\\\angle1=180\[tex]\therefore m\angle2=65\°-115\°=65\°[/tex]

Thus the measure of ∠1 is 65°.

For ∠2.

Since the given triangle is an isosceles triangle.

So, m\angle1=m\angle2

Thus the measure of ∠2 is 65°.

For ∠3.

Here ∠1, ∠2 and ∠3 are the three angles of the triangle.

So we use the angle sum property of triangle, which states that;

"The sum of all the angles of a triangle is equal to 180°".

\therefore \angle1+\angle2+\angle3=180\°

Now we put the values and get;

65\°+65\°+\angle3=180\°\\\\130\°+\angle3=180\°\\\\\angle3=180\°-130\°=50\°

Thus the measure of ∠3 is 50°.

For ∠4.

∠4 and ∠2 makes straight angle, and we know that the measure of straight angle is 180°.

So, we can frame this in equation form as;

\angle2 +\angle 4 =180\°

Substituting the values of of angle 2 to find angle 4 we get;

65\°+ \angle 4 = 180\°\\\\ \angle 4 = 180\°-65\°\\\\\angle 4= 115\°

Thus the measure of ∠4 is 115°.

For ∠5.

∠4 and ∠5 makes straight angle, and we know that the measure of straight angle is 180°.

So, we can frame this in equation form as;

\angle4 +\angle 5 =180\°

Substituting the values of of angle 4 to find angle 5 we get;

115\°+ \angle 5 = 180\°\\\\ \angle 5 = 180\°-115\°\\\\\angle 5= 65\°

Thus the measure of ∠5 is 65°.

Hence:

The measure of ∠1 is 65°.

The measure of ∠2 is 65°.

The measure of ∠3 is 50°.

The measure of ∠4 is 115°.

The measure of ∠5 is 65°.

6 0
3 years ago
Plzz Help me!! Have to have this submitted by tonight!
Aliun [14]
N is the number of the Tshirt
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∫c<br> x sin y ds, C is the line segment from (0, 1) to (3, 5)
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Parameterize the line segment C by

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where t\in[0,1]. Then

\mathrm ds=\|\mathbf r'(t)\|\,\mathrm dt
\mathrm ds=\|\langle3,4\rangle\|\,\mathrm dt
\mathrm ds=5\,\mathrm dt

So the integral is

\displaystyle\int_Cx\sin y\,\mathrm ds=5\int_0^1x(t)\sin y(t)\,\mathrm dt
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3 years ago
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