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podryga [215]
2 years ago
7

Choose the answer that shows exponential decay?*

Mathematics
1 answer:
Vlad1618 [11]2 years ago
6 0
I’m not sure what that is
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What is the simplified expression for ?
alex41 [277]
The simplified expression is 16
3 0
3 years ago
State the degree x^3y^2+7x^2y^5-3xy^8
KATRIN_1 [288]
The main formula for a polynomial ax^my^n+...
the degree is the sum of the highest degree of the polynomial, it is m+n

<span>the degree of  x^3y^2+7x^2y^5-3xy^8 is 9, because </span><span>3xy^8 is the term where we can find a highest value of power (8)
so the degree is degree of x, it is 1 + degree of y (it is 8)
</span>
4 0
3 years ago
Read 2 more answers
What is the area of the triangle in the diagram?
Vladimir [108]

1/2sqrt((x_1^2+y_1^2)(x_2^2+y_2^2))

The area of a triangle is equal to 1/2bh (one half base times height). Since this is a right triangle, the base and height are the two legs connected to the 90* angle. To find the values of these sides, we will use Pythagorean Theorem, root a squared plus b squared.

Short leg: <x(1),y(1)>

This leg can be seen as the hypotenuse of an invisible right triangle. The x value, x(1), is how far over the x value has gone from the origon at x=0. Imagine a leg alone the x-axis, going from (0,0) to (x(1),0). The y value of the point, y(1), works the same way. This leg will go from our previous mark at (x(1),0) to the point (x(1),y(1)). This shows that the short leg of the main triangle is the hypotenuse, with a height of y(1) and base of x(1). Pythagoreum Theorem shows that the length of this leg is equal to sqrt(x_1^2+y_1^2).

Long leg: <x(2), y(2)>

The same process works here, giving us sqrt(x_2^2+y_2^2).

Now for the area, we have the b and h values. Our equation reads 1/2sqrt(x_1^2+y_1^2)sqrt(x_2^2+y_2^2).

But we can simplify this (yay). The two square roots can be written together as sqrt((x_1^2+y_1^2)(x_2^2+y_2^2))

So the correct answer is 1/2sqrt((x_1^2+y_1^2)(x_2^2+y_2^2))

5 0
3 years ago
Read 2 more answers
What is 36/93 as a decimal
sukhopar [10]
<span>0.38709677419 is your answer</span>
3 0
3 years ago
The sum of two numbers is 21. The larger number is 6 less than twice the smaller number. Find the two numbers.
never [62]
The sum of two numbers
 x + y = 21
x = smaller number
y = larger number

Larger Number = y = (2x -6)
Substitute  (2x - 6) for y
x + y = 21
x + (2x - 6) = 21
3x - 6 = 21
3x = 21 + 6
3x = 27
3x / 3 = 27 / 3
x =  9
Smaller number = x = 9
Find the larger number by inserting 9 into (2x - 6)
(2x - 6)
(2(9) - 6)
18 - 6
12

So 
x = 9
y =12

Check our answer by inserting x = 9 and y = 12 into  x + y = 21
x + y =21
9 + 12 = 21
21 = 21 
So since we have 21 = 21 we know our answer is correct. 
5 0
3 years ago
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