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DIA [1.3K]
3 years ago
7

A girl scout troop sold cookies. If the girls sold 5 more boxes the second week than they did the first, and if they doubled the

sales of the second week for the third week to sell a total of 431 boxes of cookies, how many did they sell each week?
Mathematics
2 answers:
VARVARA [1.3K]3 years ago
7 0
N = first integer 
n + 1 = second integer 
n + 2 = third 
n + 3 = fourth 

the sum is 114 so: 

n + (n + 1) + (n + 2) + (n + 3) = 114 

solve: 

4n + 6 = 114 
4n = 108 
n = 27 

so 27 is your first. 
27 + 1 is your second (remember n +1 n +2 and n +3) 

so your first four integers are: 27 28 29 and 30 


(I'll also help with one) 

week one: x 
week two: x + 5 
week three: 2(x+5) or 2x + 10 

week1 + 2 + 3 = 431 

so its: 

x + (x+5) + (2x + 10) 
4x + 15 = 431 
4x = 416 
x = 104 

its then: 

week one: 104 sold 
week two: 109 sold (x + 5) 
<span>week three: 218 (2x + 10)
</span>
aleksandr82 [10.1K]3 years ago
3 0
Pueda ser que sea tres mil quinientos
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Select all the conditions for which it is possible to construct a triangle. (7.G.1.2) Group of answer choices a. A triangle with
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Answer:

  b, d, e, f

Step-by-step explanation:

Here are the applicable restrictions:

  • The sum of angles in a triangle is 180°, no more, no less.
  • The sum of the lengths of the two shortest sides exceeds the longest side.
  • When two sides and the angle opposite the shortest is given, the sine of the given angle must be at most the ratio of the shortest to longest sides.

a. A triangle with angle measures 60°, 80°, and 80° (angle sum ≠ 180°, not OK)

b. A triangle with side lengths 4 cm, 5 cm, and 6 cm (4+5 > 6, OK)

c. A triangle with side lengths 4 cm, 5 cm, and 15 cm (4+5 < 15, not OK)

d. A triangle with side lengths 4 cm, 5 cm, and a 50° angle across from the 4 cm side (sin(50°) ≈ 0.766 < 4/5, OK)

e. A triangle with angle measures 30° and 60°, and an included 3 cm side length (OK)

f. A triangle with angle measures 60°, 20°, and 100° (angle sum = 180°, OK)

_____

<em>Additional comment</em>

In choice "e", two angles and the side between them are specified. As long as the sum of the two angles is less than 180°, a triangle can be formed. The length of the side is immaterial with respect to whether a triangle can be made.

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The congruence postulates for triangles are ...

  SSS, SAS, ASA, AAS, and HL

These essentially tell you the side and angle specifications necessary to define <em>a singular triangle</em>. As we discussed above, the triangle inequality puts limits on the side lengths specified in SSS. The angle sum theorem puts limits on the angles when only two are specified (ASA, AAS).

In terms of sides and angles, the HL postulate is equivalent to an SSA theorem, where the angle is 90°. In that case, the angle is opposite the longest side (H). In general, SSA will specify a singular triangle when the angle is opposite the <em>longest</em> specified side, regardless of that angle's measure. However, when the angle is opposite the <em>shortest</em> specified side, the above-described ratio restriction holds. If the sine of the angle is <em>less than</em> the ratio of sides, then <em>two possible triangles are specified</em>.

4 0
2 years ago
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 The answer is \ \frac{11}{14}

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