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DIA [1.3K]
3 years ago
7

A girl scout troop sold cookies. If the girls sold 5 more boxes the second week than they did the first, and if they doubled the

sales of the second week for the third week to sell a total of 431 boxes of cookies, how many did they sell each week?
Mathematics
2 answers:
VARVARA [1.3K]3 years ago
7 0
N = first integer 
n + 1 = second integer 
n + 2 = third 
n + 3 = fourth 

the sum is 114 so: 

n + (n + 1) + (n + 2) + (n + 3) = 114 

solve: 

4n + 6 = 114 
4n = 108 
n = 27 

so 27 is your first. 
27 + 1 is your second (remember n +1 n +2 and n +3) 

so your first four integers are: 27 28 29 and 30 


(I'll also help with one) 

week one: x 
week two: x + 5 
week three: 2(x+5) or 2x + 10 

week1 + 2 + 3 = 431 

so its: 

x + (x+5) + (2x + 10) 
4x + 15 = 431 
4x = 416 
x = 104 

its then: 

week one: 104 sold 
week two: 109 sold (x + 5) 
<span>week three: 218 (2x + 10)
</span>
aleksandr82 [10.1K]3 years ago
3 0
Pueda ser que sea tres mil quinientos
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Step-by-step explanation:

Hello!
I'd love to help you learn.
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Now that we have the corresponding system of equations, we can graph both.

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What determines the solutions of a system of equations?

-No solution: the two lines will never intersect/does not intersect ever, which means that there are no set point where it satisfies both equations.

-One solution: the two lines intersect once and only once, meaning that there is that one set point where the x and y values both satisfy both equations.

-Multiple solutions: the two lines will intersect each other multiple times, meaning there are multiple set points where the x and y values satisfy both equations. You usually will not have to worry about these problem sets.

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Answer:

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