Question

Evaluate p(7,3) a.24 b.35 c.210

Answer 1

Answer:

P(7,3) = 210

Step-by-step explanation:

Given : P(7,3)

We have to evaluate the given permutation P(7,3)

We can define P(n,r) is defined as the number of possibilities of choosing r objects from a total of n objects.

$nPr=\frac{n!}{\left(n-r\right)!}$

For given P(7,3)

Put n = 7 and r = 3 , we have,

$=\frac{7!}{\left(7-3\right)!}$

Simplify, we have,

$=\frac{7!}{4!}$

Cancel the factorials, $\frac{n!}{\left(n-m\right)!}=n\cdot \left(n-1\right)\cdots \left(n-m+1\right),\:n>m$

$\frac{7!}{4!}=7\cdot \:6\cdot \:5$

Simplify, we have,

= 210

Thus, P(7,3) = 210

Answer 2

7P3 = 7 * 6 * 5 = 210