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1 year ago

10

If your answer is b

atex-formula">-10 what does it mean

1 answer:

adelina 88 [10]1 year ago

3 0

Answer:

This means that b is not equal to -10.

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What the factors of 40 with a sum of -22? *

Andru [333]

Answer:

Why is 90 the sum of all factors of 40, including 40? The factors of the number 40 are: 1, 2, 4, 5, 8, 10, 20, 40. If you add them up, you will get the total of 90.

Step-by-step explanation:

2. Given the points A, B, C, D, calculate:

(a) the angle B of the triangle ABC

(b) the area of the triangle ABC

(c) the median BE of the triangle ABC

(d) the height AH of the triangle ABC

(e) the volume of tetrahedron ABCD

(f) the point E so that ABCE is a parallelogram.

A(-1, 2, -3), B(4, -1, 0), C(2, 1, -2), D( 3,4,5)

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2 years ago

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Which equation describes the function shown on the graph?

Varvara68 [4.7K]

It’s no graph to give answer to

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2 years ago

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A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 30 ft/s. Its height

Crank

Answer:

a) h = 0.1: $\bar v = -11\,\frac{ft}{s}$ , h = 0.01: $\bar v = -10.1\,\frac{ft}{s}$ , h = 0.001: $\bar v = -10\,\frac{ft}{s}$ , b) The instantaneous velocity of the ball when $t = 2\,s$ is $-10$ feet per second.

Step-by-step explanation:

a) We know that $y = 30\cdot t -10\cdot t^{2}$ describes the position of the ball, measured in feet, in time, measured in seconds, and the average velocity ( $\bar v$ ), measured in feet per second, can be done by means of the following definition:

$\bar v = \frac{y(2+h)-y(2)}{h}$

Where:

$y(2)$ - Position of the ball evaluated at $t = 2\,s$ , measured in feet.

$y(2+h)$ - Position of the ball evaluated at $t =(2+h)\,s$ , measured in feet.

$h$ - Change interval, measured in seconds.

Now, we obtained different average velocities by means of different change intervals:

$h = 0.1\,s$

$y(2) = 30\cdot (2) - 10\cdot (2)^{2}$

$y (2) = 20\,ft$

$y(2.1) = 30\cdot (2.1)-10\cdot (2.1)^{2}$

$y(2.1) = 18.9\,ft$

$\bar v = \frac{18.9\,ft-20\,ft}{0.1\,s}$

$\bar v = -11\,\frac{ft}{s}$

$h = 0.01\,s$

$y(2) = 30\cdot (2) - 10\cdot (2)^{2}$

$y (2) = 20\,ft$

$y(2.01) = 30\cdot (2.01)-10\cdot (2.01)^{2}$

$y(2.01) = 19.899\,ft$

$\bar v = \frac{19.899\,ft-20\,ft}{0.01\,s}$

$\bar v = -10.1\,\frac{ft}{s}$

$h = 0.001\,s$

$y(2) = 30\cdot (2) - 10\cdot (2)^{2}$

$y (2) = 20\,ft$

$y(2.001) = 30\cdot (2.001)-10\cdot (2.001)^{2}$

$y(2.001) = 19.99\,ft$

$\bar v = \frac{19.99\,ft-20\,ft}{0.001\,s}$

$\bar v = -10\,\frac{ft}{s}$

b) The instantaneous velocity when $t = 2\,s$ can be obtained by using the following limit:

$v(t) = \lim_{h \to 0} \frac{x(t+h)-x(t)}{h}$

$v(t) = \lim_{h \to 0} \frac{30\cdot (t+h)-10\cdot (t+h)^{2}-30\cdot t +10\cdot t^{2}}{h}$

$v(t) = \lim_{h \to 0} \frac{30\cdot t +30\cdot h -10\cdot (t^{2}+2\cdot t\cdot h +h^{2})-30\cdot t +10\cdot t^{2}}{h}$

$v(t) = \lim_{h \to 0} \frac{30\cdot t +30\cdot h-10\cdot t^{2}-20\cdot t \cdot h-10\cdot h^{2}-30\cdot t +10\cdot t^{2}}{h}$

$v(t) = \lim_{h \to 0} \frac{30\cdot h-20\cdot t\cdot h-10\cdot h^{2}}{h}$

$v(t) = \lim_{h \to 0} 30-20\cdot t-10\cdot h$

$v(t) = 30\cdot \lim_{h \to 0} 1 - 20\cdot t \cdot \lim_{h \to 0} 1 - 10\cdot \lim_{h \to 0} h$

$v(t) = 30-20\cdot t$

And we finally evaluate the instantaneous velocity at $t = 2\,s$ :

$v(2) = 30-20\cdot (2)$

$v(2) = -10\,\frac{ft}{s}$

The instantaneous velocity of the ball when $t = 2\,s$ is $-10$ feet per second.

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3 years ago

A museum opened at 9:00 a.m. In the first hour, 350 people purchased admission tickets. In the second hour, 20% more people purc

Furkat [3]

Answer:

13,475

Step-by-step explanation:

First hour

350 people at $17.50 per ticket

350* $17.50 =$6125

Second hour

We add 20% more

350+350*.20 =350+70 =420

There were 420 people at $17.50

420*$17.50 =$7350

Add the total for the 2 hours

6125+7350=13,475

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3 years ago

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The curved part of this figure is a semicircle.

Nitella [24]

Draw the diameter from point (-1, -5) to point (2, 3).

The triangle has base 3 and height 8.

The diameter of the semicircle is the hypotenuse of the triangle.

$d = \sqrt{3^2 + 8^2}$

$d \approx 8.544$

The radius is half the diameter.

$r = \dfrac{d}{2} = \dfrac{8.544}{2} = 4.272$

The total area is the area of the triangle plus the area of the semicircle.

$A = \dfrac{bh}{2} + \dfrac{\pi r^2}{2}$

$A = \dfrac{3 \times 8}{2} + \dfrac{\pi \times 4.272^2}{2}$

$A = 12 + 9.125 \pi$ $units^2$

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3 years ago