Answer:
i think no i think lng po ehh
<span>Find
the values of a and b that make f continuous everywhere. f(x) = x^2 − 4
/ x − 2 if x < 2 ax^2 − bx + 3 if 2 ≤ x < 3 4x − a + b if x ≥ 3
</span>
a=7/12
b=13/2
The answer to the first question of the attached document is option 1. We obtain the answer subtracting the term n from the series with the term n-1.For example:
-3 - (- 5) = 2
-1 - (- 3) = 2
1 - (- 1) = 2
So you can see that the common difference is the 2.
The answer to the second question is option 3:
y = | x + 7 |
We can confirm it by substituting values in the equation.
For example:
if we do y = 0 then x = -7
if we do x = 0 then y = 7.
As corresponds in the graph shown.
Remember also that as a general rule yes to the equationy = | x | whose vertex is in the point (0,0) we add a positive real number "a" of form y = | x + a | then the graph of y = | x | will move "to" units in the negative direction of x.
The answer to the third question is option 4.
The quotient of x and "and" is constant.
k = y / x
Rewriting:
y = kx
You can see that it corresponds to the equation of a line that passes through the origin, this means that and is proportional to x and both vary directly
The exact answer is

but if you round it up it will equal
Solving inequalities is almost the same as solving equalities for basic cases. Only thing you've to watch out for is signs.
For example, in 2x + 3 > 5,
We may subtract 3 from both sides,
2x > 2
Hence, by dividing both sides by 2, we get x>1.
The inequality sign changes on multiplying with (-)
For example, 2 < 6
But, -2 > -6
And when you interchange a fraction
E.g. 3/4 > 2/3
But, 4/3 < 3/2
You can now solve these of your own
Try yourself