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Dmitriy789 [7]
3 years ago
6

Need some help with these last few problems Thank you for your time and help

Mathematics
1 answer:
konstantin123 [22]3 years ago
3 0
(1) On the unit circle, you have \sin x=-1 when x=-\dfrac\pi2, and more generally this is the case whenever you perform a full rotation about the origin. This means \sin x=-1 any time x=-\dfrac\pi2+2n\pi where n is any integer.

(2) When x=-90^\circ, you have y=f(-90^\circ)=\cos(-90^\circ)=0.

(3) When x=-45^\circ, you have y=f(-45^\circ)=\tan(-45^\circ)=-1.

(4) The law of sines says that

\dfrac{12}{\sin40^\circ}=\dfrac{e}{\sin55^\circ}\implies e\approx15.292

(5) The law of cosines says that

b^2=6.5^2+8^2-2\times6.5\times8\cos37^\circ\implies b\approx4.816
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Find the value of cos P rounded to the nearest hundredth, if necessary.
Leviafan [203]

Answer:

0.13

Step-by-step explanation:

cos P = adj/hyp

cos P = 2/16

cos P = 1/8 = 0.125

cos P = 0.13

7 0
2 years ago
Steve earned $7.40 per hour working his paper route. The first week, he worked 16 hours. After getting paid, he put $105 in the
prisoha [69]

Answer:17

Step-by-step explanation: Multiply Steve’s hourly wage ($7.40) by the hours he worked in a week (16 Hours) that would give you your weekly earnings which would be (7.40x16=$118.40) Then subtract what he saved in the bank from your total (118.40-105=$13.40) then you would divide $13.40 (his leftover money) by $0.75 to find the total number of carnival rides he could ride (13.40/0.75=17.86 rides and because he cannot ride 17 and 86 hundredths of a ride he would be able to ride 17 carnival rides.

6 0
3 years ago
Read 2 more answers
1<br>Prove that<br>1: sin/1-cot + cos/1-tan=cos+sin​
Anit [1.1K]

Answer:

have:

\frac{sin}{1-cot}+\frac{cos}{1-tan}\\\\=\frac{sin}{1-\frac{cos}{sin} }+\frac{cos}{1-\frac{sin}{cos} }\\\\=\frac{sin^{2} }{sin-cos}+\frac{cos^{2} }{cos-sin} \\\\=\frac{sin^{2} }{sin-cos}-\frac{cos^{2} }{cos-sin}\\\\=\frac{sin^{2}-cos^{2}  }{sin - cos}\\\\=\frac{(sin-cos)(sin+cos)}{sin-cos}\\\\=sin+cos

Step-by-step explanation:

4 0
3 years ago
6x - 2y = 5
laiz [17]

Answer:

The given system has NO SOLUTION.

Step-by-step explanation:

Here, the given system of equation is:

6 x -  2 y = 5     .......... (1)

3 x  - y = 10          .... (2)

Multiply equation 2 with (-2), we get:

3 x  - y = 10     ( x -2)

⇒  - 6 x + 2 y = - 20

Now, ADD this to equation (1) , we get:

6 x - 2 y  - 6 x + 2 y  = 5 - 20

or, 0 = - 15

WHICH IS NOT POSSIBLE as 0 ≠ -15

Hence, the given system has NO SOLUTION.

7 0
3 years ago
solve the compound inequality. graph your solution. 2x – 2 &lt; –12 or 2x 3 &gt; 7 a. x &lt; –5 or x &gt; 2 b. x &lt; –12 or x &
Kisachek [45]
2x - 2 < -12 or 2x + 3 > 7
2x < -12 + 2 or 2x > 7 - 3
2x < -10 or 2x > 4
x < -5 or x > 2
6 0
3 years ago
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