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Dmitriy789 [7]
3 years ago
6

Need some help with these last few problems Thank you for your time and help

Mathematics
1 answer:
konstantin123 [22]3 years ago
3 0
(1) On the unit circle, you have \sin x=-1 when x=-\dfrac\pi2, and more generally this is the case whenever you perform a full rotation about the origin. This means \sin x=-1 any time x=-\dfrac\pi2+2n\pi where n is any integer.

(2) When x=-90^\circ, you have y=f(-90^\circ)=\cos(-90^\circ)=0.

(3) When x=-45^\circ, you have y=f(-45^\circ)=\tan(-45^\circ)=-1.

(4) The law of sines says that

\dfrac{12}{\sin40^\circ}=\dfrac{e}{\sin55^\circ}\implies e\approx15.292

(5) The law of cosines says that

b^2=6.5^2+8^2-2\times6.5\times8\cos37^\circ\implies b\approx4.816
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Type the correct answer in each box.
Mariulka [41]

Answer:

(x-5)^2+(y+4)^2=100

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The distance between the center and any point that lie on the circle is equal to the radius

we have the points

(5,-4) and (-3,2)    

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

substitute the values

r=\sqrt{(2+4)^{2}+(-3-5)^{2}}

r=\sqrt{(6)^{2}+(-8)^{2}}

r=\sqrt{100}\ units

r=10\ units

step 2

Find the equation of the circle

we know that

The equation of a circle in standard form is equal to

(x-h)^2+(y-k)^2=r^2

where

(h,k) is the center

r is the radius

we have

(h,k)=(5,-4)\\r=10\ units

substitute

(x-5)^2+(y+4)^2=10^2

(x-5)^2+(y+4)^2=100

6 0
3 years ago
HEY CAN ANYONE HELP ME!
nataly862011 [7]

Answer:

Given: In triangle ABC and triangle DBE where DE is parallel to AC.

In ΔABC and ΔDBE

DE || AC   [Given]

As we know, a line that cuts across two or more parallel lines.  In the given figure, the line AB is a transversal.

Line segment  AB is transversal that intersects two parallel lines.  [Conclusion from statement 1.]

Corresponding angles theorem: two parallel lines are cut by a transversal, then the  corresponding angles are congruent.

then;

\angle BDE \cong \angle BAC  and

\angle BEC \cong \angle BCA

Reflexive property of equality states that if angles in geometric figures can be congruent to themselves.

by Reflexive property of equality:

\angle B \cong \angle B  

By AAA (Angle Angle Angle) similarity postulates states that all three pairs of corresponding angles are the same then, the triangles are similar

therefore, by AAA similarity postulates theorem

\triangle ABC \sim \triangle DBE

Similar triangles are triangles with equal corresponding angles and proportionate side.

then, we have;

\frac{BD}{BA}                  [By definition of similar triangles]

therefore, the missing statement and the reasons are

Statement                                                                   Reason

3.\angle BDE \cong \angle BAC      Corresponding angles theorem

and  \angle BEC \cong \angle BCA        

5. \triangle ABC \sim \triangle DBE   AAA similarity postulates    

6. BD over BA                                                    Definition of similar triangle



7 0
2 years ago
Read 2 more answers
A trail has markers every 1/8 mile. Jody starts at the 2 1/4 mile marker, hikes to the 4 3/8 marker, and then hikes back to the
vlada-n [284]
Yes I think so because she started at 2 1/4 then hiked to 4 3/8. That is roughly 2 miles and then from there she joked all the way back to 11/2? But I could be wrong?????
3 0
3 years ago
What Number is X in this equation?<br><br> 6 ÷ 2( 1 + 2 ) = X
LUCKY_DIMON [66]

Answer:

x=1.5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The 40th parallel of north latitude runs across the United States through Philadelphia, Indianapolis, and Denver. At this latitu
Ronch [10]

Answer:

793.25 mi/hr

Step-by-step explanation:

Given that:

The radius of the earth is = 3030 miles

The angular velocity = \dfrac{\pi}{12} rads

If a jet flies due west with the same angular velocity relative to the ground at the equinox;

We are  to determine the How fast in miles per hour would the jet have to travel west at the 40th parallel for this to happen.

NOW;

Distance s is expressed by the relation

s = rθ

s = 3030(\frac{\pi}{12} )

s = 793.25

The speed which depicts how fast in miles per hour the jet would have traveled is :

speed (v) = \frac{s}{t}

v = \frac{793.25}{1}

v = 793.25 mi/hr

Hence, the jet would have traveled 793.25 mi/hr due west at the  40th parallel for this to happen.

7 0
3 years ago
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