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CaHeK987 [17]
2 years ago
10

The formula W=0.86g^2-0.01g+5.9 models the weight, W, in ounces, for a cat who is fed g grams per day of a special food. Accordi

ng to the formula, how much will a cat weigh when it is fed 13 grams of the special food per day? Round to the nearest hundredth.
Mathematics
1 answer:
RUDIKE [14]2 years ago
7 0

Using the equation which models weight of cat in terms of amount of food fed, the weight of the cat will be : 151.11 ounces

<u>Given the equation</u> :

  • W=0.86g² - 0.01g +5.9

  • <em>g = Amount of food in grams </em>

<u>Substituting g = 13 into the equation</u> :

W = 0.86(13)² - 0.01(13) +5.9

W = 0.86(169) - 0.13 + 5.9

W = 145.34 - 0.13 + 5.9

W = 151.11 ounces

Therefore, the weight of the cat will be 151.11 ounces

Learn more : brainly.com/question/18796573

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Evaluate the line integral, where c is the given curve. C xeyz ds, c is the line segment from (0, 0, 0) to (2, 3, 4)
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The value of line integral is, 73038 if the c is the given curve. C xeyz ds, c is the line segment from (0, 0, 0) to (2, 3, 4)

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It is defined as the mathematical calculation by which we can sum up all the smaller parts into a unit.

The parametric equations for the line segment from (0, 0, 0) to (2, 3, 4)

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The line integral is given by:

\rm \int\limits_C {xe^{yz}} \, ds = \int\limits^1_0 {2te^{12t^2}} \, \sqrt{2^2+3^2+4^2} dt

 

\rm ds = \sqrt{2^2+3^2+4^2} dt

After solving the integration over the limit 0 to 1, we will get;

\rm \int\limits_C {xe^{yz}} \, ds = \dfrac{\sqrt{29}}{12}  (e^{12}-1)   or

= 73037.99 ≈ 73038

Thus, the value of line integral is, 73038 if the c is the given curve. C xeyz ds, c is the line segment from (0, 0, 0) to (2, 3, 4)

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brainly.com/question/18125359

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