Answer:
- 2 trees ($200 from either service)
- c=100+50t
- c=80+60t
Step-by-step explanation:
It can work well to solve problems like this by considering how many times the difference in per-tree costs it takes to make up the difference in one-time costs.
Here the difference of one-time costs is $20, and the difference in per-tree costs is $10, so it takes the pruning of 2 trees for the per-tree cost difference to equal the one-time cost difference (2×10 = 20).
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The cost equations are ...
cost = (one-time cost) + (per tree cost) × (number of trees)
c = 100 + 50t . . . . . company A
c = 80 + 60t . . . . . . company B
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If you use these equations to solve the problem, you want to find t such that the two costs are equal:
100 +50t = 80 +60t
(100 -80) = t(60 -50) . . . . . . . subtract 80+50t, factor out t
(100 -80)/(60 -50) = t . . . . . . . looks a lot like the verbal description above
The difference in fixed price divided by the difference in per-tree cost) is the number of trees required to make costs equal.
Answer:
98 sq inc
Step-by-step explanation:
Second choice- multiply by 12
Answer: 20 days
Step-by-step explanation:
Since the sale agent makes 40 calls a day and about 15% he calls result in a sale. This means the number of sales will be:
= 15% × 40
= 0.15 × 40
= 6
6 sales out of every 40 calls per day.
The number of calls to make 120 sales will be:
= 15% of x = 120
0.15 × x = 120
0.15x = 120
x = 120/0.15
x = 800 calls
Since he needs 800 calls and he makes 40 calls per day, the number of days needed will be:
= 800/40
= 20 days
Answer:
which table!!!
Step-by-step explanation:
please attach the attachment