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valkas [14]
4 years ago
15

9(9h + 4b + 9), for h = 7 and b = 3 Evaluate

Mathematics
1 answer:
irakobra [83]4 years ago
6 0
So, when adding in the 7 and 3 the new equation is:
9{(9x7)+(4x3)+9}

Following pemdas, you have to do parenthesis first. So now the equation is:
9(63+12+9)

Now distribute the 9:

567 + 108 + 81

And finally solve as a normal addition problem:

567 + 108 + 81= 756

So, the answer is 756.


I hope this helps:)
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.48x =36 x=36/.48 x=75 So the total distance to kirk's grandmother's house was 75 miles
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4 years ago
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Rewrite 5ab showing the multiplication signs
monitta

Answer:

5ab = 5 \times a \times b

Step-by-step explanation:

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Solve: x/x+2 + 5/x-3 = 25/x2-x-6
Paraphin [41]

Answer:

x1=3  x2=-5

BUT x1=3 is not an answer because it doesnt respects the range on the original ecuation, so x2=-5 is the solution

Step-by-step explanation:

6 0
3 years ago
Suppose that the functions r and a are defined for all real numbers x as follows. r(x)=2x-1 S(x)=5x write the expressions for (r
NeTakaya

\boxed{(r-s)(x)=-3x-1} \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x} \\ \\ \boxed{(r+s)(-2)=-15}

<h2>Explanation:</h2>

In this exercise, we have the following functions:

r(x)=2x-1 \\ \\ s(x)=5x

And they are defined for all real numbers x. So we have to write the following expressions:

First expression:

(r-s)(x)

That is, we subtract s(x) from r(x):

(r-s)(x)=2x-1-5x \\ \\ Combine \ like \ terms: \\ \\ (r-s)(x)=(2x-5x)-1 \\ \\ \boxed{(r-s)(x)=-3x-1}

Second expression:

(r\cdot s)(x)

That is, we get the product of s(x) and r(x):

(r\cdot s)(x)=(2x-1)(5x) \\ \\ By \ distributive \ property: \\ \\ (r\cdot s)(x)=(2x)(5x)-(1)(5x) \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x}

Third expression:

Here we need to evaluate:

(r+s)(-2)

First of all, we find the sum of functions r(x) and s(x):

(r+s)(x)=2x-1+5x \\ \\ Combine \ like \ terms: \\ \\ (r+s)(x)=(2x+5x)-1 \\ \\ (r+s)(x)=7x-1

Finally, substituting x = -2:

(r+s)(-2)=7(-2)-1 \\ \\ (r+s)(-2)=-14-1 \\ \\ \boxed{(r+s)(-2)=-15}

<h2>Learn more: </h2>

Parabola: brainly.com/question/12178203

#LearnWithBrainly

5 0
3 years ago
An element has half life of about 20 days. How much of 3000 gram sample is left after 100 days?
bagirrra123 [75]

t=100

p=3000

t 1/2 = 20

Try inserting the numbers in the half-life formula.

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