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3 years ago

9(9h + 4b + 9), for h = 7 and b = 3 Evaluate

1 answer:

6 0

So, when adding in the 7 and 3 the new equation is:
9{(9x7)+(4x3)+9}

Following pemdas, you have to do parenthesis first. So now the equation is:
9(63+12+9)

Now distribute the 9:

567 + 108 + 81

And finally solve as a normal addition problem:

567 + 108 + 81= 756

So, the answer is 756.

I hope this helps:)

You might be interested in

Suppose the dealer incentive per vehicle for honda's acura brand in 2012 is thought to be bell-shaped and symmetrical with a mea

andreev551 [17]

Answer:

From $1600 to $3400.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 2500

Standard deviation = 300

What interval of dealer incentives would we expect approximately 99.7% of vehicles to fall within?

By the Empirical Rule, 99.7% fall within 3 standard deviations frow the mean. So

From 2500 - 3*300 = 1600 to 2500 + 3*300 = 3400.

8 0

3 years ago

Erik and Caleb were trying to solve the equation: 0=(3x+2)(x-4) Erik said, "The right-hand side is factored, so I'll use the zer

Mumz [18]

Answer:

C) Both

Step-by-step explanation:

The given equation is:

$0=(3x+2)(x-4)$

To solve the given equation, we can use the Zero Product Property according to which if the product <em>A.B = 0</em>, then either A = 0 OR B = 0.

Using this property:

$(3x+2) = 0 \Rightarrow \bold{x = -\frac{2}{3}}\\(x-4) = 0 \Rightarrow \bold{x = 4}$

So, Erik's solution strategy would work.

Now, let us discuss about Caleb's solution strategy:

Multiply $(3x+2)(x-4)$ i.e. $3x^2-12x+2x-8$ = $3x^2-10x-8$

So, the equation becomes:

$0=3x^2-10x-8$

Comparing this equation to standard quadratic equation:

$ax^2+bx+c=0$

a = 3, b = -10, c = -8

So, this can be solved using the quadratic formula.

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{-(-10)\pm\sqrt{(-10)^2-4\times3 \times (-8)}}{2\times 3}\\x=\dfrac{-(-10)\pm\sqrt{196}}{6}\\x=\dfrac{10\pm14}{6} \\\Rightarrow x= 4, -\dfrac{2}{3}$

The answer is same from both the approaches.

So, the correct answer is:

C) Both

3 0

2 years ago

2) 4 6 2 3 If L= | 5 8 and M= 1 4 3 -2 -5 3 3 Find L-M -)) 2 4 8 A ) 3 4 5 2 3 B) 4 4 8 -5 6 9 o 6 12 -2 1 6 6 2 D) 9 12 1

Misha Larkins [42]

$\\ \sf\longmapsto L-M$

Put values

$\sf \left[\begin{array}{cc}\sf 4&\sf 6\\ \sf 5 &\sf 8 \\ \sf 3 &\sf -2\end{array}\right]-\left[\begin{array}{cc}\sf 2&\sf 3\\ \sf 1 &\sf 4 \\ \sf -5&\sf3\end{array}\right]$