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3 years ago

Which is an example of dealer incentives?

Mathematics

2 answers:

Scilla [17]3 years ago

4 0

Sun car dealers pay 18000 to galaxy car for a car worth20000

kramer3 years ago

3 0

Answer

The example of dealer incentives is Sun car dealers pay $18,000 to Galaxy car manufacturers for a car worth $20,000.

Step-by-step explanation:

Definition of incentive

The allowance is a rebate or discount that is applied to the vehicle price.

As the Sun car dealers pay $18000 for a car to the manufacturers for a car worth $20,000.

This shows that Sun car dealers gets some discount .

Therefore the correct example of dealer incentive is Sun car dealers pay $18,000 to Galaxy car manufacturers for a car worth $20,000.

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Looking for some furniture for her new apartment, Susan visits the local swap meet in search of something cheap. Knowing that mo

Lady_Fox [76]

The amount that Susan will have to pay in interest is given by: Option A: $5.33 approx.

<h3>How to find the percentage from the total value?</h3>

Suppose the value of which a thing is expressed in percentage is "a'

Suppose the percent that considered thing is of "a" is b%

Then since percent shows per 100 (since cent means 100), thus we will first divide the whole part in 100 parts and then we multiply it with b so that we collect b items per 100 items(that is exactly what b per cent means).

Thus, that thing in number is

$\dfrac{a}{100} \times b$

For this case, we're given that:

Amonut Susan took out = $200
Interest rate = 32% annually (interest rates are usually expressed in annual (yearly) terms).
Amount paid off within 1 month

The interest was 32% annually, so in monthly terms, it would be 32/12 = 2.667% approx. (as there are 12 months in each year)

Since the balance was paid within one month, the interest would be simply 1 time calculated on the main balance.

Thus, we get:
Interest amount ≈ 2.667% of $200 = $\dfrac{200}{100} \times 2.667 = 5.334 \approx 5.33 \: \rm (in \: dollars)$

Thus, the amount that Susan will have to pay in interest is given by: Option A: $5.33 approx.

Learn more about percent here:

brainly.com/question/11549320

8 0

2 years ago

If u(x) = x5 – x4 + x2 and v(x) = –x2, which expression is equivalent to (u/v)(x)

choli [55]

Answer:

c) -x^3 + x^2 - 1

Step-by-step explanation:

Given: u (x) = x^5 - x^4 +x^2 and v(x) = -x^2

(u/v)(x) = u(x)/v(x)

Now plug in the given functions in the above formula, we get

= (x^5 - x^4 + x^2) / -x^2

We can factorize the numerator.

In x^5 - x^4 + x^2. the common factor is x^2, so we can take it out and write the remaining terms in the parenthesis.

= x^2 (x^3 - x^2 + 1) / - x^2

Now we gave x^2 both in the numerator and in the denominator, we can cancel it out.

(u/v)(x) = (x^3 - x^2 + 1) / -1

When we dividing the numerator by -1, we get

(u/v)(x) = -x^3 + x^2 - 1

Answer: c) -x^3 + x^2 - 1

Hope you will understand the concept.

Thank you.

6 0

3 years ago

Read 2 more answers

TRUE OR FALSE <br>becomes zero for x=1<br>PLEASE HELP

Vlad1618 [11]

Answer:

is this your only question?

5 0

2 years ago

23. A certain type of gasoline is supposed to have a mean octane rating of at least 90. Suppose measurements are taken on of 5 r

Nostrana [21]

Answer:

a) $p_v =P(Z$

b) Since $p_v$ we can reject the null hypothesis at the significance level given. So based on this we can commit type of Error I.

Because Type I error " is the rejection of a true null hypothesis".

c) $P(\bar X >90)=1-P(Z$

$1-P(Z$

d) For this case we need a z score that accumulates 0.02 of the area on the right tail and 0.98 on the left tail and this value is z=2.054

And we can use this formula:

$2.054=\frac{90-89}{\frac{0.8}{\sqrt{n}}}$

And if we solve for n we got:

$n = (\frac{2.054 *0.8}{1})^2=2.7 \approx 3$

Step-by-step explanation:

Previous concepts and data given

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We can calculate the sample mean and deviation with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

$\bar X=88.96$ represent the sample mean

$s=1.011$ represent the sample standard deviation

n=5 represent the sample selected

$\alpha$ significance level

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is less than 90, the system of hypothesis would be:

Null hypothesis: $\mu \geq 90$

Alternative hypothesis: $\mu < 90$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{88.96-90}{\frac{0.8}{\sqrt{5}}}=-2.907$

Part a

P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=5-1 = 4$

Then since is a left tailed test the p value would be:

$p_v =P(Z$

Part b

Since $p_v$ we can reject the null hypothesis at the significance level given. So based on this we can commit type of Error I.

Because Type I error " is the rejection of a true null hypothesis".

Part c

We want this probability:

$P(\bar X$

The best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

If we apply this formula to our probability we got this:

$P(\bar X >90)=1-P(Z$

$1-P(Z$

Part d

For this case we need a z score that accumulates 0.02 of the area on the right tail and 0.98 on the left tail and this value is z=2.054

And we can use this formula:

$2.054=\frac{90-89}{\frac{0.8}{\sqrt{n}}}$

And if we solve for n we got:

$n = (\frac{2.054 *0.8}{1})^2=2.7 \approx 3$

7 0

3 years ago

What is the sum of the polynomials? (6x+7x+x^2)+(2x^2-3x)

Trava [24]

Answer:

3x^2 + 10x

Step-by-step explanation:

4 0

3 years ago