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e-lub [12.9K]
3 years ago
14

Dairon needs 20 pieces of string 3/8 inch in length. He cut a 4 7/8 inch piece of string into pieces that are 3/8 of an inch lon

g each. How many more pieces of string does he need?

Mathematics
1 answer:
kramer3 years ago
8 0
The 4 7/8 = 39/8 = 13 pieces of string, he needs 20 so he will need to cut 7 more pieces
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Meg mixes 3 parts silver paint with 4 parts green paint to get a specific color. Is the ratio 5:6 equivalent to 3:4?
damaskus [11]

Answer:

No, because the numbers in the given ratio must be multiplied by the same number.

Step-by-step explanation:

Essentially, ratio to be equal must be equal. E.g. 3:4 would be equal to 6:8 because you multiply both sides of the ratio by 2.

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Which system of equations below has infinitely many solutions? y = –3x 4 and y = –3x – 4 y = –3x 4 and 3y = –9x 12 y = –3x 4 and
Flura [38]

the equations y = –3x + 4 and 3y = –9x + 12 have infinitely many solutions. option B is correct.

<h3>What is the linear system?</h3>

It is a system of an equation in which the highest power of the variable is always 1. A one-dimension figure that has no width. It is a combination of infinite points side by side.

Condition for the parallel lines.

L1,  ax + bx + c = 0

L2, dx + ey + f = 0

If \rm \dfrac{a}{d} = \dfrac{b}{e} = \dfrac{c}{f} then lines have infinitely many solutions.

<h3>Which system of equations below has infinitely many solutions?</h3>

y = –3x + 4 and 3y = –9x + 12

On comparing we have

a = -3 , b = 1, and c = 4

d = -9 , e = 3, and f = 12

Then their ratio will be

\rm \dfrac{1}{3} = \dfrac{-3}{-9} = \dfrac{4}{12}\\\\\rm \dfrac{1}{3} = \dfrac{1}{3} = \dfrac{1}{3}

Hence  y = –3x + 4 and 3y = –9x + 12 have infinitely many solutions.

Thus the option B is correct.

More about the linear system link is given below.

brainly.com/question/20379472

7 0
2 years ago
Find an equation for the nth term of the arithmetic sequence.
Irina18 [472]

Answer:

The equation of the nth term is an = -621 + 42n

Step-by-step explanation:

* Lets revise the arithmetic sequence

- There is a constant difference between each two consecutive numbers

- Ex:

# 2  ,  5  ,  8  ,  11  ,  ……………………….

# 5  ,  10  ,  15  ,  20  ,  …………………………

# 12  ,  10  ,  8  ,  6  ,  ……………………………

* General term (nth term) of an Arithmetic sequence:

- U1 = a  ,  U2  = a + d  ,  U3  = a + 2d  ,  U4 = a + 3d  ,  U5 = a + 4d

- Un = a + (n – 1)d, where a is the first term , d is the difference

  between each two consecutive terms

, n is the position of the term

* Lets solve the problem

∵ an = a + (n - 1)d

∴ a14 = a + (14 - 1)d

∴ a14 = a + 13d

∵ a14 = -33

∴ a + 13d = -33 ⇒ (1)

- Similar we can find another equation from a15

∵ a15 = a + (15 - 1)d

∴ a15 = a + 14d

∵ a15 = 9

∴ a + 14d = 9 ⇒ (2)

- We will solve equations (1) and (2) to find a and d

* Lets subtract equation (2) from equation (1)

∴ (a - a) + (13 - 14)d = (-33 - 9)

∴ -d = -42 ⇒ × both sides by -1

∴ d = 42

- Substitute this value of d in equation (1) or (2)

∵ a + 13d = -33

∵ d = 42

∴ a + 13(42) = -33

∴ a + 546 = -33 ⇒ subtract 546 from both sides

∴ a = -579

* Now lets write the equation of the nth term

∵ an = a + (n - 1)d

∵ a = -579 and d = 42

∴ an = -579 + (n - 1) 42 ⇒ open the bracket

∴ an = -579 + 42n - 42

∴ an = -621 + 42n

* The equation of the nth term is an = -621 + 42n

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3 years ago
Please help me on this work please !
belka [17]
The second one I beileve is the answer to your question
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