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fredd [130]
4 years ago
8

Please Help Me!!!

Mathematics
2 answers:
vladimir1956 [14]4 years ago
6 0
MJP and PJR is EQUAL!
LJP and NJR is EQUAL
KJL and LJM is UNEQUAL!
KJR and MJP is (I'm not really sure about this one but I believe its equall!


frozen [14]4 years ago
5 0
Question 1:

We know,

∠LJK = 42°

∠MJN = 46°

∠PJQ = 48°

∠QJR = 46°

From figure,

∠MJK = 90°

∠MJL + ∠LJK = 90

∠MJL + 42 = 90

∠MJL = 90 - 42

∠MJL = 48°

Hence, the angles that are equal are:

∠MJL and ∠PJQ, ∠MJN and ∠QJR

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The probability of randomly selecting two oranges from a bowl of 5 oranges and 4 tangerines if the first selection is replaced
denis-greek [22]

Answer:

25/81

Step-by-step explanation:

The probability of randomly selecting two oranges = (number of oranges in the bowl / total number of fruits in the bowl) x (number of oranges in the bowl / total number of fruits in the bowl)

total number of fruits in the bowl = 5 + 4 = 9

5/9 x 5/9 = 25/81

6 0
3 years ago
Find the equation of the line that is perpendicular to the line x=-7 and contains the point (-6,8)
Alex73 [517]

Answer:

The equation would be y = 8

Step-by-step explanation:

Since the line x = -7 is a vertical line, we know that any line perpendicular to it would be horizontal. All horizontal lines can be written as y = (a number). Since we have an ordered pair that is on the line, we can find that number as the y value in that pair.

y = 8

4 0
4 years ago
In ΔDEF, the measure of ∠F=90°, the measure of ∠D=20°, and EF = 92 feet. Find the length of FD to the nearest tenth of a foot.
Mashutka [201]

Answer:

FD ≈ 252.8 feet

Step-by-step explanation:

By applying tangent rule in the given right triangle,

tan(20°) =  

tan(20°) =  

0.36397 =  

FD =  

FD = 252.77

FD ≈ 252.8 feet

3 0
3 years ago
What is the answer to 5
Feliz [49]

Answer:

6

Step-by-step explanation:

bejsnsjsnsjsnsjmdkd

4 0
3 years ago
Read 2 more answers
Find the squares of (y+3) ​
emmasim [6.3K]

Answer:

Since we know that

(a+b)

2

=a

2

+2ab+b

2

(a−b)

2

=a

2

−2ab+b

2

Now,

(i)

(x+3y)

2

=x

2

+2×x×3y+(3y)

2

=x

2

+6xy+9y

2

(ii)

(2x−5y)

2

=(2x)

2

−2×2x×5y+(5y)

2

=4x

2

−20xy+25y

2

(iii)

(a+

5a

1

)

2

=a

2

+2×a×

2a

1

+(

2a

1

)

2

=a

2

+1+

4a

2

1

(iv)

(2a−1a)=(1a)

2

(1a)

2

=1a

2

Answer

8 0
3 years ago
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