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sdas [7]
3 years ago
9

Saige's spaceship traveled 588 km in 60 sec. Determine whether or not each spaceship trip below has the same speed as Saige's sp

aceship.

Mathematics
1 answer:
Nostrana [21]3 years ago
8 0

Answer:

only 441 km in 45 s has the same speed as Saige's

Step-by-step explanation:

588 / 60 = 9.8 km/sec

441 / 45 = 9.8 km/sec

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We can fix this problem easily by turning 3/8 and 1/4 into alike denominator fractions.

We can turn 1/4 into 2/8 as it is equivalent fractions.

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Once we get this, we can see that Shen spent 2/8 hours on his homework while he spent 3/8 hours on his math assignment.

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