For this case we can propose a rule of three according to the Shontaro base performance.
4 hits ------------> 12 times at bat
x -------------------> 36 times at bat
Where "x" represents the number of hits he will have the following week, based on his previous performance.
So, Shintaro will have 12 hits in 36 times at bat
Answer:
Shintaro will have 12 hits in 36 times at bat
OPtion B
Answer:
Maximum volume = 649.519 cubic inches
Step-by-step explanation:
A rectangular piece of cardboard of side 15 inches by 30 inches is cut in such that a square is cut from each corner. Let x be the side of this square cut. When it was folded to make the box the height of box becomes x, length becomes (30-2x) and the width becomes (15-2x).
Volume is given by
V =
First, we differentiate V(x) with respect to x, to get,
Equating the first derivative to zero, we get,
Solving, with the help of quadratic formula, we get,
,
Again differentiation V(x), with respect to x, we get,
At x =
,
Thus, by double derivative test, the maxima occurs at
x = for V(x).
Thus, largest volume the box can have occurs when .
Maximum volume =