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diamong [38]
3 years ago
15

What is the solution for the systems of equations

Mathematics
1 answer:
AlekseyPX3 years ago
5 0
x=1, y=2

Solve the following system:
{y = 5 - 3 x5 x - 4 y = -3
Substitute y = 5 - 3 x into the second equation:
{y = 5 - 3 x5 x - 4 (5 - 3 x) = -3

5 x - 4 (5 - 3 x) = (12 x - 20) + 5 x = 17 x - 20:{y = 5 - 3 x17 x - 20 = -3

In the second equation, look to solve for x:{y = 5 - 3 x17 x - 20 = -3

Add 20 to both sides:{y = 5 - 3 x17 x = 17

Divide both sides by 17:{y = 5 - 3 xx = 1

Substitute x = 1 into the first equation:{y = 2x = 1
Collect results in alphabetical order:Answer:  {x = 1                y = 2
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Please help :):):):):):):):......
Gelneren [198K]
13+13=26
9+9=18
18+26=44

Hope this helps :)
3 0
3 years ago
Read 2 more answers
What are the x- and y-intercepts of 2x+4y=8
NeX [460]

x-intercept: (4,0)

y-intercept: (0,2)

8 0
3 years ago
Colton left his house for work and was gone 5 hours. He spent a total of } hour driving to and from work and didn't go anywhere
Solnce55 [7]

Answer:

4\frac{3}{4}  hours

Step-by-step explanation:

he was gone for 5 \frac{1}{4} hours, he spent \frac{1}{2} an hour driving.

5 \frac{1}{4} - \frac{1}{2} = 4\frac{3}{4} hours at  work.

6 0
3 years ago
3(x + 1) = 5(x - 2) + 7 x=?
alukav5142 [94]
1.4 repeating? 


3x+3=5x-10+7x
3x+3=12x-10
3=9x-10
13=9x
1.4 repeating=x
4 0
3 years ago
Read 2 more answers
[(2x)^x (2x)^2x]^1/x<br>how do you simplify this?
Monica [59]
Note that [ (2x)^x ]^(1/x) = 2x, and that [ (2x)^(2x) ]^(1/x) = (2x)^2 = 4x^2

Multiplying these 2 results together, we get (2x)(4x^2) = 8x^3 (answer)
5 0
3 years ago
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