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icang [17]
3 years ago
6

-5(y+3)-6 less than y+3

Mathematics
1 answer:
kenny6666 [7]3 years ago
6 0
-5(y+3) < y+3  (GIVEN)
-5y+-15 < y+3 (DISTRIBUTE)
-15 < 6y+3 (ISOLATE VARIABLE)
-18 < 6y (ISOLATE VARIABLE)
-3 < y (DIVIDE) 
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the sum of the digits of a two number is 14 .if 36 is substracted from the number,the places of the digits are reversed.find the
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The number in the ones place= X
The number in the tenths place= y
y+x=14.
y=14-x

Original placement of numbers=10y+x
New placement of numbers(after subtraction of 36)= 10x+y

10y+ x-36=10x+y
Substitute y with 14-x
So we would get

10(14-x)+ x-36=10x+(14-x)
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After transposing we get
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x=5

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=14-5
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So the two digit number is
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∆PQR has vertices P(5, –2), Q(1, –4), and R(3,3).Reflect ∆PQR about the y-axis, translate 4 units down, and reflect about the x-
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D is equivalent because brackets don’t change anything here
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Read 2 more answers
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