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allochka39001 [22]
2 years ago
8

What is an equation of the line that passes through the point (−8,−1) and is parallel to the line x-4y=4x

Mathematics
1 answer:
avanturin [10]2 years ago
5 0

Answer:

y = -3/4x - 7

Step-by-step explanation:

Parallel lines have the same slope.

Solve for y in the equation to find the slope.

x - 4y = 4x

  -4y = -x + 4x

  -4y = 3x

     y = 3/-4 x   = -3/4x    So the slope is -3/4  which is the coefficient of the

                                       x term

Substitute the slope(m) = -3/4 and point (-8, -1) into y = mx + b to solve for "b"

y = mx + b

-1 = -3/4(-8) + b

-1 = 6 + b

-1 - 6 = b

-7 = b

The equation of the new line:  y = mx + b

                                                  y = -3/4x - 7

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