Answer:
2 units
Step-by-step explanation:
Given data
The points are (2, 3) and (2, 5)
x1= 2
y1= 3
x2= 2
y2= 5
substitute into the distance between two points formula
d=√((x_2-x_1)²+(y_2-y_1)²)
d=√((2-2)²+(5-3)²)
d=√(2)²)
d=√4
d= 2 units
Hence the length is 2 units
Answer:
$50,581.9
Step-by-step explanation:
Part 1We are given

. This can be rewritten as

.
Therefore, a=1, b=-18, c=0.
Using the quadratic formula

The values of x are
Part 2Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a
quadratic function. Part 3.The first equation is

.
The second equation is

.
We have

Factoring, we have

Equating both factors to zero.

When the value of x is 6, the value of y is

When the value of x is -3, the value of y is

Therefore, the solutions are (6,38) or (-3,11)
3x + 2y = 10 .....multiply by -2
2x + 3y = 15/2...multiply by 3
------------------
-6x - 4y = -20 (result of multiplying by -2)
6x + 9y = 22.5 (result of multiplying by 3)
-----------------add
5y = 2.5
y = 2.5/5
y = 1/2
3x + 2y = 10
3x + 2(1/2) = 10
3x + 1 = 10
3x = 10 - 1
3x = 9
x = 9/3
x = 3
solution is (3,-1/2)
Answer:
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