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3 years ago

15

There are 8 competitors in each ring for a tae kwon do tournament. If there are 96 competitors in the tournament, how many rings

do they need?

2 answers:

Svetlanka [38]3 years ago

7 0

12 :)
WORK
96 / 8 = 12
HOPE I HELPED ;0

Marysya12 [62]3 years ago

5 0

All you need to do is divide 96 by 8 and you get 12 as your answer

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4/5 divided by 1/3 plus 1/5 minus 3/5

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Answer:

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Step-by-step explanation:

Considering the expression

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

Solution Steps:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

as

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so

$=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}$

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so

$=\frac{4}{5\left(-\frac{1}{15}\right)}$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=\frac{4}{-5\cdot \frac{1}{15}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}$

$=-\frac{4}{5\cdot \frac{1}{15}}$

$\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}$

so

$=-\frac{4}{\frac{1}{3}}$

$\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}$

so

$=-\frac{12}{1}$

$\mathrm{Apply\:rule}\:\frac{a}{1}=a$

$=-12$

Therefore

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

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Step-by-step explanation:

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