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WINSTONCH [101]
3 years ago
14

Pls help i’m so confused!!

Mathematics
1 answer:
pentagon [3]3 years ago
3 0

Answer:

11 units^2

Step-by-step explanation:

We know that the area of a square is the side squared, so we can use the inverse of this formula to say the side of a square is the square root of the the area. This gives us√33 and √44 as the side lengths of the red and green squares respectively. Next, we use the pythagorean theorem to find the other side of the white right triangle, which is also a side of the blue square. So:

(√44)^2 - (√33)^2 = side^2

44 - 33 = side

side^2 = 11

side = √11

To find the area of a square, you just square the side, so we get (√11)^2 which is just 11 units^2.

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Which of the following phrases translates to the expression n - 8?
weqwewe [10]

Answer:

B. eight fewer than a number

3 0
4 years ago
Read 2 more answers
Brainliest to the correct answer :)
frozen [14]

Answer:

Assume that the formula is true for the (k+1)term

Step-by-step explanation:

I learned this in class a couple weeks ago in intermediate algebra

7 0
3 years ago
Can Someone Answer My Final Answers :) I’d appreciate it so much :)
DaniilM [7]
1. Remember that the perimeter is the sum of the lengths of the sides of a figure.To solve this, we are going to use the distance formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}
where
(x_{1},y_{1}) are the coordinates of the first point
(x_{2},y_{2}) are the coordinates of the second point
Length of  WZ:
We know form our graph that the coordinates of our first point, W, are (1,0) and the coordinates of the second point, Z, are (4,2). Using the distance formula:
d_{WZ}= \sqrt{(4-1)^2+(2-0)^2}
d_{WZ}= \sqrt{(3)^2+(2)^2}
d_{WZ}= \sqrt{9+4}
d_{WZ}= \sqrt{13}

We know that all the sides of a rhombus have the same length, so 
d_{YZ}=  \sqrt{13}
d_{XY}= \sqrt{13}
d_{XW}= \sqrt{13}

Now, we just need to add the four sides to get the perimeter of our rhombus:
perimeter= \sqrt{13} + \sqrt{13} + \sqrt{13} + \sqrt{13}
perimeter=4 \sqrt{13}
We can conclude that the perimeter of our rhombus is 4 \sqrt{13} square units. 

2. To solve this, we are going to use the arc length formula: s=r \alpha
where
s is the length of the arc. 
r is the radius of the circle.
\alpha is the central angle in radians

We know form our problem that the length of arc PQ is \frac{8}{3}  \pi inches, so s=\frac{8}{3} \pi, and we can infer from our picture that r=15. Lest replace the values in our formula to find the central angle POQ:
s=r \alpha
\frac{8}{3} \pi=15 \alpha
\alpha =  \frac{\frac{8}{3} \pi}{15}
\alpha = \frac{8}{45} \pi

Since \alpha =POQ, We can conclude that the measure of the central angle POQ is \frac{8}{45} \pi

3. A cross section is the shape you get when you make a cut thought a 3 dimensional figure. A rectangular cross section is a cross section in the shape of a rectangle. To get a rectangular cross section of a particular 3 dimensional figure, you need to cut  in an specific way. For example, a rectangular pyramid cut by a plane parallel to its base, will always give us a rectangular cross section. 
We can conclude that the draw of our cross section is:

6 0
3 years ago
Read 2 more answers
Please please please can someone help me :)
disa [49]

Answer:

Step-by-step explanation:

now the equation looks like

3-4Cos(x)=y

hmmm i'm wondering if you can figure it out from here???  it's the same as the other two.. plug in that \sqrt{2} /2  .. can you?   :)

8 0
3 years ago
Let v1 = (-6,4) and v^2 = (-3,6). Compute the following<br> V^1 * V^2
Vesnalui [34]
It is just the multiplication of vectors. We'll multiply corresponding pairs together. The general formula for the pairs of (x_{1}; y_{1}) and (x_{2}; y_{2}) is x_{1} * x_{2} + y_{1} *  y_{2} = (-6)*(-3)+4*6=18+24=42
7 0
3 years ago
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