Answer:
-8.2,-2.5,.4,2.4
Step-by-step explanation:
start by negatives. negatives are lesser the higher they are. so -8.2 is less than -2.5. then positives are greater than negatives. .4 is less than 2.4. hope this helps
Answer:
a) 0.8505
b) 0.1241
c) 0.2736
d) 0.1495
Step-by-step explanation:
Answer:
a) (76.21,83.79)
b) (77.32,82.68)
c) Interval decreases
Step-by-step explanation:
We are given the following information in the question:
Sample size, n = 60
Sample mean = 80
Sample standard Deviation, s = 15
a) 95% Confidence interval:

Putting the values, we get,


b) Sample size, n = 120
95% Confidence interval:

c) As observed increasing the sample size, the confidence interval become smaller.