All categories

3 years ago

I really need help!

Mathematics

1 answer:

mario62 [17]3 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

at 2 P.M the level of the water in the pool was 10 feet. At 6 P.M the level of water was 2 feet. Find the constant rate of chang

Anna35 [415]

Decreases by 2ft every hour

3 0

3 years ago

1. {26, 69, 30, 27, 19, 54, 27} Mean: , Median: , Mode: , Range:

den301095 [7]

Answer:

Mean:36

Median:27

Mode:27

Range:50

Step-by-step explanation:

Mean: 19+26+27+27+30+53+69/7=36

Median: The middle number in the sequence when arranged in ascending order which is 27

Mode: The number that appeared more than others which is 27

Range: This is the difference between the largest number and the lowest number in the sequence which is 50.

IF THIS HELPS PLEASE MARK ME AS BRAINLIEST

5 0

2 years ago

What is the factorise 12x+8

34kurt

12x+8
Answer is =4(3x+2)

3 0

3 years ago

A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y

siniylev [52]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32

Given that 100 beetles are released into a field.

So that means initial number of beetles P=100

Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

$A=P(1+r)^n$ where A is number of beetles at any year n.

Plug the given values into above formula we get:

$A=100(1+0.32)^n$

$A=100(1.32)^n$

now plug n=10 years

$A=100(1.32)^{10}=100(16.0597696605)=1605.97696605$

Hence answer is approx 1606 beetles will be there after 20 years.

Now we have to find about how many beetles will there be in 20 years.

To find that we plug n=20 years

$A=100(1.32)^{20}=100(257.916201549)=25791.6201549$

Hence answer is approx 25791 beetles will be there after 20 years.

Now we have to find time for 100000 beetles so plug A=100000

$A=100(1.32)^n$

$100000=100(1.32)^n$

$1000=(1.32)^n$

$log(1000)=n*log(1.32)$

$\frac{\log\left(10000\right)}{\log\left(1.32\right)}=n$

33.174666862=n

Hence answer is approx 33 years.

4 0

3 years ago

Read 2 more answers

A Ferris wheel has a diameter of 56 ft. how far will a rider travel during a 4-minute ride if the wheel rotates once every 20 se

Luba_88 [7]

First calculate the circumference. Usually this is the diameter times pi, but since we are told to estimate pi, the circumference equals 56 * 22/7 or 176 feet.
In 4 minutes, 4 * 60 = 240 seconds pass. In this time, a 20 second period will occur 240/20 = 12 times.
So we know that the rider rotates 12 times and each rotation takes them 176 feet, meaning that they will travel 12 * 176 = 2112 feet

5 0

3 years ago