Question

In chickens, having feathers on legs is dominant to having featherless legs. In a population of 200 chickens, 128 have featherless legs. How many chickens are heterozygous for the "feathered leg" allele? Assume the population is in Hardy-Weinberg equilibrium

Answer 1

Answer:

Number of heterozygous population 64

Explanation:

Given data:

Total population of chicken 200

Number of chicken having  featherless legs 128, that represent q2 (as they are homozygous recessive)

Total number of chickens = 200

Therefore, the value of $q^2 = \frac{128}{200} = 0.64$

$q^2 = 0.64$

so q = 0.8, and

p = 1 - q

   = 1 - 0.8 = 0.2

The frequency of$2pq = 2 \times 0.8 \times 0.2 = 0.32$

Therefore, Number of heterozygous population$= 0.32 \times 200 = 64$