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3 years ago

50 pointssssssss Simplify the following. Please leave it in exponential form.3^8 × 1/3^1

Mathematics

2 answers:

nikitadnepr [17]3 years ago

7 0

Answer:

2187

Step-by-step explanation:

skelet666 [1.2K]3 years ago

5 0

Answer:

3^7

Step-by-step explanation:

We know that $3^8=3\cdot3^7$ and since it's multiplied by $\frac{1}{3}$ which is the same thing as $\frac{1}{3}^1$ we know that $3\cdot\frac{1}{3}\cdot3^7=3^7$ .

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Leno4ka [110]

Answer:

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Step-by-step explanation:

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3 years ago

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RoseWind [281]

Square root of 4 is 2
Square root of 9 is 3
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3 years ago

What is the surface area of the triangular prism?

SCORPION-xisa [38]

Answer:

300yd²

Step-by-step explanation:

Surface Area = area of triangles *2 + area of thhe 3 rectangles

SA= 2*( 9*4/2) + 5*12 + 8*12 + 9*12= 2*18 +5*12 + 8*12 + 9*12 =

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3 years ago

Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.

Harrizon [31]

Answer:

Equation of the line that passes through the given point and is (a) parallel is: $\mathbf{y=-2x+11}$

Equation of the line that passes through the given point and is (b) perpendicular is: $\mathbf{y=\frac{1}{2}x+1}$

Step-by-step explanation:

We need to Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.

First we will find slope of the line given in graph

The slope can be found using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We have points (1,6) and (2,2)

Slope is:

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{2-6}{2-1}\\Slope=\frac{-4}{2}\\Slope=-2$

Part a)

Write an equation of the line that passes through the given point and is (a) parallel

When the lines are parallel, they have same slope. So, slope of required line: m = -2

Using slope m =-2 and point(4,3) we can find y-intercept b

$y=mx+b\\3=-2(4)+b\\3=-8+b\\b=3+8\\b=11$

The equation of line will be:

$y=mx+b\\y=-2x+11$

Equation of the line that passes through the given point and is (a) parallel is: $\mathbf{y=-2x+11}$

Part b)

Write an equation of the line that passes through the given point and is (b) perpendicular

When the lines are perpendicular they have opposite slope. So, slope of required line: m = 1/2

Using slope m =1/2 and point(4,3) we can find y-intercept b

$y=mx+b\\3=\frac{1}{2}(4)+b\\3=2+b\\b=3-2\\b=1$

The equation of line will be:

$y=mx+b\\y=\frac{1}{2}x+1$

Equation of the line that passes through the given point and is (b) perpendicular is: $\mathbf{y=\frac{1}{2}x+1}$

6 0

3 years ago

Verify the associative law (ab)c=a(bc)(ab)c=a(bc) as follows:

Airida [17]

Verify the associated law

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3 years ago