4 years ago

Round to the nearest hundred thousand on a number 89,659

Mathematics

1 answer:

KATRIN_1 [288]4 years ago

6 0

Your answer is 90,000

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Answer:

The distance of point ( 6 , 2 ) from line 6 x - y = 3 is $\frac{31}{\sqrt{37} }$ unit .

Step-by-step explanation:

Given as :

The equation of line is 6 x - y = 3

And The points is ( 6 , 2 )

Let The distance between the line and points is d unit

So, The distance of point from the line = $\frac{\begin{vmatrix}ax & +b y & + c\end{vmatrix}}{\sqrt{a^{2}+b^{2}}}$

Or, d = $\frac{\begin{vmatrix}6\times x & +(-1)\times y & + (-3)\end{vmatrix}}{\sqrt{6^{2}+(-1)^{2}}}$

Or, d = $\frac{\begin{vmatrix}6\times 6 & +(-1)\times 2 & + (-3)\end{vmatrix}}{\sqrt{6^{2}+(-1)^{2}}}$

Or, d = $\frac{36 - 2 - 3}{\sqrt{37} }$

∴ d = $\frac{31}{\sqrt{37} }$ unit

Hence The distance of point ( 6 , 2 ) from line 6 x - y = 3 is $\frac{31}{\sqrt{37} }$ unit . Answer

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