Answer:
140 ml
Step-by-step explanation:
Let x be the amount of water in Beaker X and y be the amount of water in Beaker Y.
<u>Then we get following equations:</u>
<u>First part</u>
- x - 50 = 3/7(y + 50)
- 7x -350 = 3y + 150
- 7x = 3y + 500
<u>Second part</u>
- x + 100 = 4(y - 100)
- x + 100 = 4y - 400
- x = 4y - 500
<u>Substitute x in first equation:</u>
- 7(4y - 500) = 3y + 500
- 28y - 3500 = 3y + 500
- 28y - 3y = 500 + 3500
- 25y = 4000
- y = 4000/25
- y = 160 ml
<u>Then finding x:</u>
- x = 4*160 - 500
- x = 640 - 500
- x = 140 ml
Initial amount of water in Beaker X is 140 ml, in Beaker Y is 160 ml
The coordinates of D is (3,-1) i’m pretty sure if not i’m sorry.
Find the perimiter now
that is right triangle so
when hpotonouse is c and hthe lgs are a and b
a²+b²=c²
given
leg is 8
hypotonuse is 13
8²+b²=13²
64+b²=169
minus 64 from both sides
b²=105
sqrt both sides
b=√105
find total perimiter
8+13+√105=21+√105
times 1/32 for scale
0.65625+0.32021721143623744947565745876628=
0.97646721143623744947565745876628 m=
97.646721143623744947565745876628 cm
A is the answer
it has gone up 4 lines and left -2 making it go for a (4,-2)
The range is all positive values...
R{y | y>0}
Range > "Y" such that y is greater than 0
