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Vlad [161]
3 years ago
9

On a coordinate plane, 2 lines are shown. Line P Q has points (negative 8, 2) and (4, 2). Line M N has points (8, 6) and (8, neg

ative 8). What is the slope of line PQ? What is the slope of line MN? How are the two lines related?
Mathematics
2 answers:
DaniilM [7]3 years ago
4 0

Answer:

Slope of PQ = 0

Slope of MN = infinity

PQ and MN are perpendicular to each other

Step-by-step explanation:

for any two points  (x1, y1),  (x2, y2)given in coordinate plane slope is given by

y1 - y2/x1-x2\\\\For \ line \ PQ\\slope = 2 - 2/-8-4 = 0\\\\For \ line \ MN \\slope = 6 - (-8)/8-8 = 1/0 = infinity\\\\

For any line if slope is zero it is parallel  to X axis and perpendicular to Y axis

For any line if slope is infinity it is parallel  to Y axis and perpendicular to X axis

Also we know X and Y are perpendicular to each other.

Since slope of PQ is zero it is parallel  to X axis and perpendicular to Y axis

Since slope of MN is infinity it is parallel  to Y axis and perpendicular to X axis.

Thus two lines PQ and MN are perpendicular to each other.

Olin [163]3 years ago
4 0

Answer

Given,

Points of the line PQ are (-8,2) and (4,2)

Slope of the line

m_1 = \frac{y_2-y_1}{x_2-x_1}

m_1 = \frac{2-2}{4+8}

m_1 = 0

Points of the line MM are (8,-6) and (8,-8)

Slope of the line

m_2 = \frac{y_2-y_1}{x_2-x_1}

m_2 = \frac{2-2}{4+8}

Line PQ is parallel to x-axis and pass through y = 2.

Line MN is parallel to y-axis and pass through x = 8.

Both line intersect at (8,2).

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