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4 years ago

Someone please help thank you!!!!

Mathematics

1 answer:

Ratling [72]4 years ago

8 0

"The perimeter P..." gives us one variable to work with.

"is" in this context almost always means "equals".

"the sum" we know we will be adding.

"twice the length l" gives us a variable and a coefficient.

"twice the width w" gives us a variable and a coefficient.

The equation for this is P=2l+2w

I hope in the future you can remember these tips! :)

You might be interested in

300 hundreds= how many tens! Pls answer ASAP

Svetradugi [14.3K]

Answer:

300÷10=30

Step-by-step explanation:

hope this helps

8 0

3 years ago

Read 2 more answers

Alice searches for her term paper in her filing cabinet, which has several drawers. She knows thatshe left her term paper in dra

katen-ka-za [31]

You made a mistake with the probability $p_{j}$ , which should be $p_{i}$ in the last expression, so to be clear I will state the expression again.

So we want to solve the following:

Conditioned on this event, show that the probability that her paper is in drawer $j$ , is given by:

(1) $\frac{p_{j} }{1-d_{i}p_{i} } , if j \neq i,$ and

(2) $\frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} } , if j = i.$

so we can say:

$A$ is the event that you search drawer $i$ and find nothing,

$B$ is the event that you search drawer $i$ and find the paper,

$C_{k}$ is the event that the paper is in drawer $k, k = 1, ..., n.$

this gives us:

$P(B) = P(B \cap C_{i} ) = P(C_{i})P(B | C_{i} ) = d_{i} p_{i}$

$P(A) = 1 - P(B) = 1 - d_{i} p_{i}$

Solution to Part (1):

if $j \neq i$ , then $P(A \cap C_{j} ) = P(C_{j} )$ ,

this means that

$P(C_{j} |A) = \frac{P(A \cap C_{j})}{P(A)} = \frac{P(C_{j} )}{P(A)} = \frac{p_{j} }{1-d_{i}p_{i} }$

as needed so part one is solved.

Solution to Part(2):

so we have now that if $j$ = $i$ , we get that:

$P(C_{j}|A ) = \frac{P(A \cap C_{j})}{P(A)}$

remember that:

$P(A|C_{j} ) = \frac{P(A \cap C_{j})}{P(C_{j})}$

this implies that:

$P(A \cap C_{j}) = P(C_{j}) \cdot P(A|C_{j}) = p_{i} (1-d_{i} )$

so we just need to combine the above relations to get:

$P(C_{j}|A) = \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} }$

as needed so part two is solved.

8 0

4 years ago

The given line passes through the points (-2,-4) and (2,2) What is the equation, in point-slope form, of the line that is parall

Morgarella [4.7K]

Answer:

$(y-1)=\frac{3}{2}(x+3)$

Step-by-step explanation:

The point slope form of a line is $(y-y_1)=m(x-x_1)$ where $x_1=-3\\y_1=1$ . We write

$(y-1)=m(x--3)\\(y-1)=m(x+3)$

Since the line is parallel to the line shown it will have the same slope. To find m, count the slope from each marked point on the graph. Count the rise then the run and create a fraction rise/run. The slope is 6/4 which simplifies to 3/2. Now substitute it for m.

$(y-1)=\frac{3}{2}(x+3)$

3 0

4 years ago

What is the sum of the interior angels of a regular polygon with 7 sides. choices are

Oksi-84 [34.3K]

Sum of Interior Angles of any poligon, where n is the number of sides: =

(n-2) × 180°

---------------------

(7 - 2) * 180° =

5 * 180 =

900°

[d]

7 0

3 years ago

Solve:

Nuetrik [128]

Answer:

Step-by-step explanation:

3x^2 - 5x + 12 - (5x^2 + x - 11) =

3x^2 - 5x + 12 - 5x^2 - x + 11 =

-2x^2 - 6x + 23 <====

4 0

3 years ago