How to solve y= -3/2 x and then I have to graph It

Mathematics

1 answer:

Ket [755]3 years ago

8 0

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

Here, an equation of straight line is given.

The equation is $y = -\frac{3x}{2}$ .

If you put x = 0, in the above equation, you will get y = 0.

Hence, the equation passes through (0, 0).

Again if we put, x = 1 in the above equation, we will get y = - 1.5.

It means the equation also passes through (1, -1.5).

Joining these two points, you can graph the straight line.

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Find two unit vectors orthogonal to both given vectors. i j k, 4i k

Maurinko [17]

The cross product of two vectors gives a third vector $\mathbf v$ that is orthogonal to the first two.

$\mathbf v=(\vec i+\vec j+\vec k)\times(4\,\vec i+\vec k)=\begin{vmatrix}\vec i&\vec j&\vec k\\1&1&1\\4&0&1\end{vmatrix}=\vec i+3\,\vec j-4\,\vec k$

Normalize this vector by dividing it by its norm:

$\dfrac{\mathbf v}{\|\mathbf v\|}=\dfrac{\vec i+3\,\vec j-4\,\vec k}{\sqrt{1^2+3^2+(-4)^2}}=\dfrac1{\sqrt{26}}(\vec i+3\,\vec j-4\vec k)$

To get another vector orthogonal to the first two, you can just change the sign and use $-\mathbf v$ .