Well, It would be hard to write out the formula and everything here so I wrote it out for you! Work shown!
The tree diagram is constructed and attached below in the image.
First we have to make a choice out of 3 subjects, so the probability of choosing art as the first subject is 1/3.
Once we have chosen art as the first subject, we have two choices. So the probability of choosing each option now is 1/2. Thus, the probability of choosing math, science is 1/2.
The probability of choosing the projects in order of art, math, science = 1/3 x 1/2 = 1/6
Therefore, the probability that the projects are in order of art, math, science is 1/6 (one over 6). So first option gives the correct answer.
For this Q:
mean=31
st.dev.=0.8
x=32
Calculate z-score:
z=(x-m)/s = (32-31)/0.8=1.25
This z-score value corresponding to the probability of 0.8944
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We can let x and y represent cups of lemonade and numbers of lemon bars, respectively. Then the constraints are ...
- x ≥ 150
- y ≥ 0
- 2x +1.5y ≥ 500
- 0.25x +0.20y ≤ 100
A graph is shown in the attachment, with the ordered pairs plotted. It is not feasible to sell half cups of lemonade or half lemon bars, so the second and third choices must be excluded. The point (160, 110) falls outside the feasible region, so is not a correct choice.
The correct choices are ...