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mr Goodwill [35]
3 years ago
6

Help me -2 (8 - e) = 2 - e​

Mathematics
1 answer:
-BARSIC- [3]3 years ago
3 0

Answer:

e = 6

Step-by-step explanation:

Step 1: Write equation

-2(8 - e) = 2 - e

Step 2: Solve for <em>e</em>

  1. Distribute -2: -16 + 2e = 2 - e
  2. Add e to both sides: -16 + 3e = 2
  3. Add 16 to both sides: 3e = 18
  4. Divide both sides by 3: e = 6

Step 3: Check

<em>Plug in e to verify it's a solution.</em>

-2(8 - 6) = 2 - 6

-2(2) = -4

-4 = -4

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Answer:

Step-by-step explanation:

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Answer:

For the tickets sold collum, your going to do 1,2,3,4,5,6,7 and for the total revenue, your going to do 34.00 68.00 102.00 136.00 170.00 204.00 238.00

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mart [117]
3.) An extreme value refers to a point on the graph that is possibly a maximum or minimum. At these points, the instantaneous rate of change (slope) of the  graph is 0 because the line tangent to the point is horizontal. We can find the rate of change  by taking the derivative of the function.

y' = 2ax + b

Now that we where the derivative, we can set it equal to 0.

2ax + b = 0

We also know that at the extreme value, x = -1/2. We can plug that in as well.

2a (-\frac{1}{2} ) + b = 0

The 2 and one-half cancel each other out.

-a + b = 0

a = b

Now we know that a and b are the same number, and that ax^2 + bx + 10 = 0 at x = -1/2. So let's plug -1/2 in for x in the original function, and solve for a/b.

a(-0.5)^2 + a(-0.5) + 10 = 0

0.25a - 0.5a + 10 = 0

-0.25a = -10

a = 40

b = 40

To determine if the extrema is a minima or maxima, we need to go back to the derivative and plug in a/b.

80x + 40

Our critical number is x = -1/2. We need to plug a number that is less than -1/2  and a number that is greater than -1/2 into the derivative.

LESS THAN:
80(-1) + 40 =  -40

GREATER THAN:
80(0) + 40 = 40

The rate of change of the graph changes from negative  to positive at x = -1/2, therefore the extreme value is a minimum.

4.) If the quadratic function is symmetrical about x = 3, that means that the minimum or maximum must be at x = 3.

y' = 2ax + 1

2a(3) + 1 = 0

6a = -1

a = -1/6

So now plug the a value and x=3 into the original function to find the extreme value.

(-1/6)(3)^2 + 3 + 3 = 4.5

The extreme value is 4.5


7 0
3 years ago
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