Answer:
11482 ppt of Li
Explanation:
The lithium is extracted by precipitation with B(C₆H₄)₄. That means moles of Lithium = Moles B(C₆H₄)₄. Now, 1 mole of B(C₆H₄)₄ produce the liberation of 4 moles of EDTA. The reaction of EDTA with Mg²⁺ is 1:1. Thus, mass of lithium ion is:
<em>Moles Mg²⁺:</em>
0.02964L * (0.05581mol / L) = 0.00165 moles Mg²⁺ = moles EDTA
<em>Moles B(C₆H₄)₄ = Moles Lithium:</em>
0.00165 moles EDTA * (1mol B(C₆H₄)₄ / 4mol EDTA) = 4.1355x10⁻⁴ mol B(C₆H₄)₄ = Moles Lithium
That means mass of lithium is (Molar mass Li=6.941g/mol):
4.1355x10⁻⁴ moles Lithium * (6.941g/mol) = 0.00287g. In μg:
0.00287g * (1000000μg / g) = 2870μg of Li
As ppt is μg of solute / Liter of solution, ppt of the solution is:
2870μg of Li / 0.250L =
<h3>11482 ppt of Li</h3>
Pyridine is an organic compound having molecular formula and hydrogen chloride has the chemical formula .
In structure of pyridine, nitrogen is attached with one of the carbons present in the benzene ring.
Now, when pyridine reacts with hydrogen chloride results in the formation of pyridinium chloride. In this reaction, hydrogen form bond with nitrogen due to the lone pair present on the nitrogen and gives +1 charge on the nitrogen with negative charge on chlorine.
The complete reaction is shown in the image.
V(rms) = √(3RT/M)
Where R is the molar gas constant with value 8.314 and T is the temperature in Kelvin and M is the molar mass
v(rms F₂) = √(3 x 8.314 x 304 / 38)
v(rms F₂) = 14.1 m/s
v(rms Cl₂) = √(3 x 8.314 x 304 / 71)
v(rms Cl₂) = 10.3 m/s
v(rms Br₂) = √(3 x 8.314 x 304 / 160)
v(rms Br₂) = 6.88 m/s
Balanced reaction: A(g) + 2B(g) ⇄ 4C(g) + D(g).
Kp = [C]⁴·[D] / [A]·[B]².
<span>[A] - equilibrium concentration of reactant A.
</span>[B] - equilibrium concentration of reactant B
[C] - equilibrium concentration of product C.
[D] - equilibrium concentration of product D.
The substances on the right side of the reaction are written at the top of the Kp<span> expression and those on the left at the bottom.</span>