About 46.1 pounds of apple would be needed per day of the trip.
I managed to extract the complete scenario from the attached image.
The trip is made up of 4 men and 3 women, making a total of 7 people.
Everyone has become accustomed to 1500 calories per day.
The total calories needed per day for 7 persons = 1500 x 7
= 10,500 calories
189 g of apple has only 95 calories, what g of apple will produce 10,500 calories?
= 10,500 x 189/95 = 20,889.67 g of apple
From conversion:
1 g = 0.00220462 pounds
20,889.67 g = 20,889.67 x 0.00220462
= 46.1 pounds of apple
More about dimensional analysis can be found here: brainly.com/question/22015862
The answer you're looking for is B. The bond will be ionic.
Answer:
The mixture contains 8.23 g of Ar
Explanation:
Let's solve this with the Ideal Gases Law
Total pressure of a mixture = (Total moles . R . T) / V
We convert T° from °C to K → 85°C + 273 = 358K
3.43 atm = (Moles . 0.082 L.atm/mol.K . 358K) / 6.47L
(3.43 atm . 6.47L) / (0.082 L.atm/mol.K . 358K) = Moles
0.756= Total moles from the mixture
Moles of Ar + Moles of H₂ = 0.756 moles
Moles of Ar + 1.10 g / 2g/mol = 0.756 moles
Moles of Ar = 0.756 moles - 0.55 moles H₂ → 0.206
We convert the moles to g → 0.206 mol . 39.95 g / 1 mol = 8.23 g
A) Fe⁰ ----> Fe⁺³ +3e⁻ oxidation | *2
b) <u>Cu⁺² + 2e⁻ -----> Cu⁰ reduction |*3</u>
c) 2Fe⁰ +3Cu⁺² -----> 2Fe⁺³ + 2Cu⁰
The answer will be 17.9 grams
