The amount of seawater that will be displaced would be 1.3274 x
<h3>Density and volume</h3>
Density = mass/volume.
Since a floating object displaces its own weight, a 4247 tons ship will also displace the same amount of water.
4247 tons of seawater = 3.8528 x g
volume of 3.8528 x g seawater = mass/density = 3.8528 x g/1.025 = 3758829268.29 cubic centimeter.
3758829268.29 = 132741.80 or 1.3274 x
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Answer:
The correct answer is option (6).
Explanation:
A molecule is group of atoms of same or different kinds of element.
In carbon monoxide there is a single carbon atom and single oxygen atom. Hence, a molecule.
Compound is defined as a chemical specie which is made by the combination of different atoms.
As we can see from the chemical formula of carbon monoxide is made up of two atom of different elements that is carbon and oxygen.
A pure substance is defined as the substance which is formed by same or different type of atoms which are chemically combined in a fixed ratio by mass. They have definite set of properties.
1 mole of carbon combined with 0.5 moles of oxygen gas to give carbon monoxide gas.
I think you forgot to give the choices along with your question. I am answering the question based on my research and knowledge. "Helium effuses 0.71 times faster than hydrogen" is the statement that <span>holds true when the molar mass of hydrogen is 2.0 grams and that of helium is 4.0 grams. I hope the answer has helped you.</span>
Ionization enthalpy, IE, is also called ionization potential is the ability to remove the electron from the neutral gaseous atom. There is a trend observed in the periodic table for the IE value. As we go from left to right in a period, IE vale increases. While moving from top to bottom in a group, IE value decreases.
- The phenomenon of unexpected drop in IE1 values between Groups 2 and 13, in period 2 and period 4 is due to the introduction of d-orbitals in the case of period 4 elements.
- While moving in the period, there is the constant addition of electrons in the nucleus. The shell sie remains constant while electron pull increases from the nucleus, this leads to a reduction in the size of the atom. As the size decreases, it is difficult to remove the electron from the atom, and thus IE value increases in the case of period 2.
- When we study the case of period 4, there is an introduction of d-electrons. As the inner shell electron increases, there is an increase in the shielding effect. This shielding effect tends to decrease the nuclear attraction between the nucleus and outermost electrons. Ultimately this decreases the IE value in the fourth period. Such a phenomenon is absent in the case of group 2 elements.
- If we speak in terms of orbital energy, the IE value decreases while moving from top to bottom in the period. This is due to the fact that, as we go down in the periodic table, the number of shells increases, and the outermost electron is too far from the nuclear attraction, therefore it can be ejected out easily. This marks a decrease in IE value.
To learn more about ionization refer the link:
brainly.com/question/1558319
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