Step-by-step explanation:
from what I can see there are 2 options to make the 2 triangles congruent :
either the opposite sides must be equal or the neighboring sides must be equal.
so, either
5x = 3x + 10
and
5x - 2 = 4x + 3
or
5x = 4x + 3
and
5x - 2 = 3x + 10
for the first
5x = 3x + 10
2x = 10
x = 5
control
5x - 2 = 4w + 3
5×5 - 2 = 4×5 + 3
23 = 23
correct.
for the second
5x = 4x + 3
x = 3
control
5×3 - 2 = 3×3 + 10
15 - 2 = 9 + 10
13 = 19
no, not a valid solution.
so, x = 5
Answer:
D
Step-by-step explanation:
Roots into factors:
x = -4 ----> (x + 4)
x = i -----> (x - i)
x = 5 -----> (x - 5)
(x + i)(x - 4)(x + 5)
(x - i)(x² - 4x + 5x - 20)
(x - i)(x² + x - 20)
x³ + x² - 20x - (ix² + ix - 20i)
x³ + (1 - i)x² - (20 + i)x + 20i
To do this make x and y equal 0, y-intercept is at x=0, and x-intercept is at y=0:
x-intercept:
2x+7(0) = -14
2x = -14
x = -7
y-intercept:
2(0) + 7y = -14
7y = -14
y = -2
Answer:
True
Step-by-step explanation:
Given that a function is
We are to find the slant asymptote if any for this function
Since numerator is of degree 2 and denominator 1, let us divide and then check
Doing long division we find
![f(x)=\frac{1}{2} [x-\frac{5}{2} ]-\frac{11}{4(2x-3)}](https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B1%7D%7B2%7D%20%5Bx-%5Cfrac%7B5%7D%7B2%7D%20%5D-%5Cfrac%7B11%7D%7B4%282x-3%29%7D)
Thus we find the asymptote y= the quotient obtained i.e
![\frac{1}{2} [x-\frac{5}{2} ]\\=\frac{x}{2} -\frac{5}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Bx-%5Cfrac%7B5%7D%7B2%7D%20%5D%5C%5C%3D%5Cfrac%7Bx%7D%7B2%7D%20-%5Cfrac%7B5%7D%7B4%7D)
Hence asymptote is
Statement given is true.
Each variable used is the first letter of each of their names.
t+b+c=87
c=2t
b=t+7
Substitute for b and c
t+ (t+7)+2t= 87
4t+7=87
4t=80
t=20
Plug in the known t value.
c=2(20)
c=40
b=20+7
b=27
Final answer: Tammy=$20, Boris= $27, Carlos=$40
