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Ede4ka [16]
3 years ago
14

What is the domain of f(x) = 3

Mathematics
2 answers:
Zinaida [17]3 years ago
4 0

Step-by-step explanation:

the domain of the function is the set of all real numbers

{x|x ∈ R}

irina [24]3 years ago
4 0

Answer:all real numbers

Step-by-step explanation: f(x) =3 means that Y is 3 for every value of X, as there's no X affected in the formula, so it will have that value always.

As there are also no restrictions, like 1/X or logX then you know that every value of X is possible to be replaced in f(x) fórmula [if there were any X in the formula, which is not the case]

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The combined volume of two identical cubes is 250 cubic centimeters. What is the measure of one cubes edge how do you determine
klio [65]
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3 years ago
Please help me solve this problem ASAP
Andru [333]
Quadrant 4
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4 0
2 years ago
Write an equation in slope intercept form of the line that passes through the given point and is paraell to the graph of the equ
Nostrana [21]
1.) x = -3...this is a vertical line with an undefined slope. A parallel line to a vertical line is also a vertical line. A vertical line is represented by x = a number....that number being the x coordinate of ur point(4,2).
so ur parallel line is : x = 4 <==
=================
2.) y = -3/2x + 6....slope here is -3/2. A parallel line will have the same slope.

y = mx + b
slope(m) = -3/2
(2,-1)...x = 2 and y = -1
now we sub into the formula and find b, the y int
-1 = -3/2(2) + b
-1 = -3 + b
-1 + 3 = b
2 = b
so ur parallel line is : y = -3/2x + 2 <==
===================
y = -x - 2....the slope here is -1. A parallel line will have the same slope

y = mx + b
slope(m) = -1
(2,-2)...x = 2 and y = -2
now we sub into the formula and find b, the y int
-2 = -1(2) + b
-2 = -2 + b
-2 + 2 = b
0 = b
so ur parallel equation is : y = -x + 0 which can be written as : y = -x <=
8 0
3 years ago
What is the arc measure of BDC in degrees?<br> (4k + 159)<br> P<br> (2k + 153)
andre [41]
<h2>Explanation:</h2><h2></h2>

The diagram is missing but I'll assume that the arc BDC is:

(4k + 159)^{\circ}

And another arc, let's call it FGH. measures:

(2k + 153)^{\circ}

If those arc are equal, then this equation is true:

(4k + 159)^{\circ}=(2k + 153)^{\circ} \\ \\ (4k + 159)=(2k + 153) \\ \\ \\ Solving \ for \ k: \\ \\ 4k-2k=153-159 \\ \\ 2k=-6 \\ \\ k=-\frac{6}{2} \\ \\ k=-3

Substituting k into the first equation:

\angle BDC=(4(-3)+159)^{\circ} \\ \\ \angle BDC=(-12+159)^{\circ} \\ \\ \boxed{\angle BDC=147^{\circ}}

3 0
3 years ago
Read 2 more answers
1. Find the slope of the line that goes through the points (2, 5) and (6, 7)
ella [17]

Answer:

\displaystyle m = \frac{1}{2}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)
  • Slope Formula: \displaystyle m = \frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Point (2, 5)

Point (6, 7)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute in points [Slope Formula]:                                                              \displaystyle m = \frac{7-5}{6-2}
  2. [Fraction] Subtract:                                                                                           \displaystyle m = \frac{2}{4}
  3. [Fraction] Simplify:                                                                                            \displaystyle m = \frac{1}{2}
7 0
3 years ago
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