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3 years ago

I NEED HELP PLZZZ!!!!!!

Mathematics

2 answers:

trasher [3.6K]3 years ago

3 0

Pretty sure the answer is D, if you simplify it, you will have 1/5

Svetlanka [38]3 years ago

3 0

Answer:

Hope that helps!

Step-by-step explanation:

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A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height

Lina20 [59]

Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

$y(t)=43t-23t^{2}$

B) Instantaneous Velocity at t = 1

$y(1) = 43(1)-23(1)^2 = 20$

A) Formula:

Average velocity =

$\displaystyle\frac{\text{Displacement}}{\text{Time}}$

1) 0.01

$y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}$

2) 0.005 s

$y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}$

3) 0.002 s

$y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}$

4) 0.001 s

$y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}$

3 0

3 years ago

What expression is equivalent to 2(m-5)+6? 2m-1 2m+22 2m-4 2m+16

DENIUS [597]

2(m - 5) + 6PEMDASu multiply 2 into (m-5)2*m and 2*-5that would be 2m-10 + 6now subtract common variables-10 + 6 = -42m - 4

7 0

3 years ago

Can someone tell me what 8 x 1 1/2 equals

Lady_Fox [76]

8 x 1 = 8
8 x 1/2 = 4
8+4 =12
therefore, 8 x 1 1/2 = 12

7 0

4 years ago

Read 2 more answers

Helpppppp asapppppopoo

wlad13 [49]

Answer: Choice A

Raising something to the 1/4th power is the same as applying the 4th root to that expression. Raising an expression to the 1/n power is the same as applying the nth root.

Rule:
$x^{1/n} = \sqrt[n]{x}$
(if the text is too small it basically says x to the (1/n) = square root with a small 'n' all over x)

4 0

3 years ago

32 + 64x - 40y (please factor it)

Lana71 [14]

The answer factored is
8(4+8x-5y)

5 0

3 years ago