3 years ago

The derivative of f(x) = e^xinx

Mathematics

1 answer:

aksik [14]3 years ago

4 0

Answer:

e^xsinx · (sinx+xcosx)

Step-by-step explanation:

f'(x)=e^xsinx · (xsinx)'= e^xsinx · (sinx+xcosx)

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Answer:

$(x,y)=(0,\frac{-2}{3})$

Step-by-step explanation:

Given : Vertices of Triangle $P(x_1,y_1)=(-4,-1)$ , $Q(x_2,y_2)=(2, 2)$ and $R(x_3,y_3)=(2,-3)$

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The centroid of a triangle is the point of intersection of the three medians of the triangle.

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$(x,y)=(\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3})$

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$(x,y)=(\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3})$

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Help is greatly appreciated:)

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Well there are 6 units down and 11 units across so 6•11=66. there are 14 red units. 66-14=52. the area of yellow is 52.

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The derivative of f(x) = e^xinx​

The derivative of f(x) = e^xinx